11 electrons , 11 protons , 12 neutrons.
Answer:
P₂ = 261 KPa
Explanation:
Given data:
Volume of sample = 200 mL
Initial pressure = 110 KPa
Initial temperature = 275 K
Final volume = 95 mL
Final temperature = 310 K
Final pressure = ?
Solution:
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₂ = P₁V₁T₂ /T₁ V₂
P₂ = 110 KPa× 200 mL× 310 K /275 K × 95 mL
P₂ = 6820000 KPa / 26125
P₂ = 261 KPa
Answer:
group
Explanation:
elements in the same group have the same number of valence electrons
Explanation:
Mg(s) + Cr(C2H3O2)3 (aq)
Overall, balanced molecular equation
Mg(s) + Cr(C2H3O2)3(aq) --> Mg(C2H3O2)3(aq) + Cr(s)
To identify if an element has been reduced or oxidized, the oxidation number is observed in both the reactant and product phase.
An increase in oxidation number denotes that the element has been oxidized.
A decrease in oxidation number denotes that the element has been reduced.
Oxidation number of Mg:
Reactant - 0
Product - +3
Oxidation number of Cr:
Reactant - +3
Product - 0
Note: C2H3O2 is actually acetate ion; CH3COO- The oxidatioon number of C, H and O do not change.
Oxidized : Mg
Reduced : Cr
