Question

Find the equation of the line containing (3,-2) and (5,5).

Answer 1

Answer:

y = 3.5x - 12.5

Step-by-step explanation:

First, find the slope using rise over run (y2 - y1 / x2 - x1) with the 2 points:

(-2 - 5) / (3 - 5)

-7/-2

= 3.5

Then, plug the slope and a point into y = mx + b to solve for b:

y = mx + b

5 = 3.5(5) + b

5 = 17.5 + b

-12.5 = b

Plug the slope and the y intercept into the equation y = mx + b

y = 3.5x - 12.5 will be the equation

Answer 2

Answer:

y=7/2x-12.5

Step-by-step explanation:

use the y=mx+b and the $\frac{y2-y1}{x2-x1}$ method

$\frac{5-(-2)}{5-3}$

7/2= thats ur slope

now plug in the slope and one of the point into the y=mx+b method

-2=7/2(3)+b

-2=21/2+b

subtract 21/2 both sides

-25/2 or -12.5

ik this doesnt make sense but hope this helps