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Vsevolod [243]
3 years ago
7

A physics student stands at the top of a hill that has an elevation of 56 meters. He throws a rock and it goes up into the air a

nd then falls back past him and lands on the ground below. The path of the rock can be modeled by the equation y=-0.04x^2+1.3x+56 where x is the horizontal distance, in meters, from the starting point on the top of the hill and y is the height, in meters, of the rock above the ground.
How far horizontally from it's starting point will the rock land? Round your answer to the nearest hundredth.

A. 56.00m
B. 24.54m
C. 57.04m
D. 57.26m
Mathematics
1 answer:
Virty [35]3 years ago
3 0
round your answer to the nearest hundredth place the answer is a
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Maysoun drove 1116 kilometers in 12 hours. At the same rate, how long would it take her to drive 651 kilometers?
Lilit [14]

Answer:

7 hours

Step-by-step explanation:

12hrs=1116kms

1hr=1116÷12

1hr=93kms

Xhrs=651kms

Xhrs=(651÷93) ×1

=7×1

=7hrs

7 0
3 years ago
A loaf of bread that is baked today costs $7. All of the bread baked yesterday is 40% off.
vovikov84 [41]

Answer:

The price of today's bread is $7.

40% of $7 is $2.80.

The price of yesterdays bread is $7-$2.80.

7-2.80=4.20

The price of yesterday's bread is $4.20

Tobin has enough money to purchase a loaf of yesterday's bread.

Hope this helps!

4 0
3 years ago
Y=3x+4 and crosses through the point (1,8)
erma4kov [3.2K]
The answer is  your equation does not pass though the point (1,8)
3 0
3 years ago
An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.
Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0.\overline 1 yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0.\overline 1 yd. =  (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³

Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel  pad, m₁ = ρ × V₁

∴ The mass of the steel  pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

∴ C = 4,050 lbs × $55/lb = $222,750

6 0
3 years ago
QUESTION 3 [10 MARKS] A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the nu
Andru [333]

Answer:

(a)Revenue=580x-10x²,

Marginal Revenue=580-20x

(b)Fixed Cost, =900

Marginal Cost,=300+50x

(c)Profit Function=280x-900-35x²

(d)x=4

Step-by-step explanation:

The price, p = 580 − 10x where x is the number of cakes sold per day.

Total cost function,c = (30+5x)²

(a) Revenue Function

R(x)=x*p(x)=x(580 − 10x)

R(x)=580x-10x²

Marginal Revenue Function

This is the derivative of the revenue function.

If R(x)=580x-10x²,

R'(x)=580-20x

(b)Total cost function,c = (30+5x)²

c=(30+5x)(30+5x)

=900+300x+25x²

Therefore, Fixed Cost, =900

Marginal Cost Function

This is the derivative of the cost function.

If c(x)=900+300x+25x²

Marginal Cost, c'(x)=300+50x

(c)Profit Function

Profit, P(x)=R(x)-C(x)

=(580x-10x²)-(900+300x+25x²)

=580x-10x²-900-300x-25x²

P(x)=280x-900-35x²

(d)To maximize profit, we take the derivative of P(x) in (c) above and solve for its critical point.

Since P(x)=280x-900-35x²

P'(x)=280-70x

Equate the derivative to zero

280-70x=0

280=70x

x=4

The number of cakes that maximizes profit is 4.

5 0
3 years ago
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