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Goshia [24]
3 years ago
11

I need the answer asap .! help please !

Mathematics
1 answer:
shtirl [24]3 years ago
8 0

Answer:

i tried the math and if im correct it should be 0.52N

Step-by-step explanation:

im sorry if its not correct bro

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What is the value of the 35th term in the sequence -15, -11, -7, ...? 121 125 151 374
Andreas93 [3]

Answer:

121

Step-by-step explanation:

This is an arithmetic sequence.

First term  a = -15

Common difference [d] = second term - first term

                                  = -11 - [-15] = -11 + 15 = 4

nth term = a + (n-1) * d

35th term = -15 + (35 - 1) * 4

                = -15 + 34 * 4

                = - 15 + 136

                = 121

8 0
4 years ago
Read 2 more answers
How do you triple rhe surface area of a cone
Gelneren [198K]
Increase the height so that the slant height triples.

For example:
  Say that lateral height is 2 and the radius is 1. The lateral surface area would be 6.28

 if I make the lateral height 6, which is triple the original lateral height, the lateral surface area becomes 18.84, which is triple the original surface area

Hope I help :P

3 0
3 years ago
Ethan Doran is a physical therapist. His biweekly salary is $3,985. What is his annual salary? (Hint: You need to know how many
NNADVOKAT [17]
103,610.00 you welcome.
7 0
3 years ago
Suppose that 5 out of 13 people are to be chosen to go on a mission trip. In how many ways can these 5 be chosen if the order in
algol [13]

5 People can be chosen  in 1287 ways if the order in which they are chosen is not important.

Step-by-step explanation:

Given:

Total number of students= 13

Number of Students to be selected= 5

To Find :

The number of ways in which the 5 people can be selected=?

Solution:

Let us use the permutation and combination to solve this problem

nCr=\frac{(n)!}{(n-r)!(r)!}

So here , n =13  and r=5 ,  

So after putting the value  of n and r , the equation will be

13C_5=\frac{(13)!}{(13-5)!(5)!}

13C_5=\frac{(13 \times12 \times11 \times10 \times9 \times8\times7 \times6 \times5 \times4 \times3 \times2 \times1)}{(8 \times7 \times6 \times5 \times4 \times3 \times2 \times1)(5 \times4 \times3 \times2 \times1)}

13C_5=\frac{(13 \times12 \times11 \times10 \times9 )}{((5 \times4 \times3 \times2 \times1)}

13C_5=\frac{154440}{120}

13C_5= 1287

8 0
4 years ago
A credit card company offers a cash back program on transactions. For every transaction over​ $100 the customer gets ​$3 back. F
Elena L [17]
The first equation is $3 times 9 = $27 the next equation iis $1 times 2 = $1
So you do 9 transactions over $100 and 2 transactions of $100 or lower. 


5 0
3 years ago
Read 2 more answers
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