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3 years ago

23)

Mathematics

1 answer:

Kaylis [27]3 years ago

8 0

Answer:

90 degrees

Step-by-step explanation:

Step 1: State what is known

Notice that the 2 lines cut the square in half and create 4 congruant triangles. We know a full circle is 360 degrees and the intersection is a perfect circle formed by 4 angles. We can find the angle AEB by dividing 360 by 4 which gives you 90 degrees

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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B80%7D%20" id="TexFormula1" title=" \sqrt[3]{80} " alt=" \sqrt[3]{80} " ali

Marianna [84]

Start by decomposing the number inside the root into primes

Then group the terms into cubes if possible

$\begin{gathered} 80=2\cdot2\cdot2\cdot2\cdot5 \\ 80=2^3\cdot2\cdot5 \\ 80=10\cdot2^3 \end{gathered}$

rewrite the root

$\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}$

then cancel the terms that are cubes and bring them out of the root

$\sqrt[3]{80}=2\sqrt[3]{10}$

7 0

1 year ago

What is the area of the obtuse triangle below?

kolezko [41]

Answer:

198

Step-by-step explanation:

just multiply 22 by 8

8 0

3 years ago

A used automobile dealership recently reduced the price of a used compact car by 6%. If the price of the car before discount was

Alchen [17]

Answer:

The discount = $1,128

New price = $17,672

Step-by-step explanation:

Price of car before discount = $18,800

Discount given = 6% of price of car

Discount value in dollars = 6% of $18,800 = 6/100*$18,800 = $1,128

Thus, the discount is $1,128

New price = Price of car before discount - discount = $18,800- $1,128

New price = $17,672

7 0

3 years ago

If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person se

notsponge [240]

Answer:

2.28% probability that a person selected at random will have an IQ of 110 or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 100, \sigma = 5$