Answer:
Hi there!
I believe you are missing an attachment to this question however
I strongly believe that the answer you are looking for is 85.
Explanation:
If you provide the graph, the rate of strokes in Asian women will be 17 per 1,000 women so all you have to do is multiply 17 by 5 and you get 85
crop rotation, green manure, and bone meal
Explanation:
I just looked it up. hope it helps
Since the pressure is constant, you can use the equation V₁/T₁=V₂/T₂ and solve for T₂. (T₂=(T₁/V₁)V₂)
since this is a gas law type question, the temperatures need to be in kelvin therefore you need to convert 15°C to kelvin. 15°C+273=288K. The volume are already in L so they don't have to be converted.
now you just need to plug everything in:
T₂=(288K/99L)x1200L
T₂=3491K
The answer is you need if you have a 99L of gas at 288K, you have to increase the temperature to 3491K to get a volume of 1200L if the pressure remains constant.
I hope this helps. Let me know in the comments if anything is unclear.
Answer: ![\frac{V_1}{V_2}=\frac{n_1}{n_2}](https://tex.z-dn.net/?f=%5Cfrac%7BV_1%7D%7BV_2%7D%3D%5Cfrac%7Bn_1%7D%7Bn_2%7D)
Explanation:
According to the Avogadro's law, the volume of gas is directly proportional to the number of moles of gas at same pressure and temperature. That means,
![V\propto n](https://tex.z-dn.net/?f=V%5Cpropto%20n)
or,
![\frac{V_1}{V_2}=\frac{n_1}{n_2}](https://tex.z-dn.net/?f=%5Cfrac%7BV_1%7D%7BV_2%7D%3D%5Cfrac%7Bn_1%7D%7Bn_2%7D)
where,
= initial volume of gas
= final volume of gas
= initial moles of gas
= final moles of gas
The answer to this question would be: lower molar concentration
Osmotic pressure is influenced by the number of ions and the concentration of the molecule in the solution. In NaCl, the molecule will split into 1 Na+ ion and 1 Cl- ion which results in 2 ions per compound. In MgCl2, the compound will split into 1 Mg2+ ion and 2 Cl- ion which results in 3 ions. Therefore, the osmotic pressure of MgCl2 will be 3/2 times of NaCl.
MgCl2 will need less concentration to achieve same osmotic pressure as NaCl. If the MgCl2 solution is isotonic with NaCl, the concentration of MgCl2 would be lower than NaCl