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goblinko [34]
3 years ago
13

How many moles of He are in 16g of the element

Chemistry
2 answers:
Maurinko [17]3 years ago
4 0
Molar mass of helium is 4.00<span> g/mol.</span>
Mole (mol): The number of particles (atoms or molecules) in a.
sample of element or compound with a mass in grams equal to the.
<span>atomic (or molecular) weight.</span>
Katyanochek1 [597]3 years ago
3 0

Answer:

4 moles of He

Explanation:

We have, 16g of He (Helium).

To calculate the number of moles in given amount of a substance, we have the formula.

\text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}}.

Here, we have 16g of He.

So, \text{Given mass}=16g

Molar mass of He is 4g

On substituting the values in the equation, we get

\text{Number of moles} = \frac{\text{16}}{\text{4}}

\text{Number of moles}=4 \text{moles of He}

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You have 15 grams of ice at 0°C. How much energy is needed to melt the ice and warm it to 25°C. Ice melts at 0°C. The specific h
azamat

Answer:

d. 1600 calories

Explanation:

The heat of fusion of water, L, is the amount of heat per gram required to melt the ice to water, a process which takes place at a constant temperature of 0 °C. The specific heat of water, c, is the amount of heat required to change the temperature of 1 gram of water by 1 degree Celsius.

We will convert the units of c from Jg⁻¹°C⁻¹ to cal·g⁻¹°C⁻¹ since the answers are provided in calories. The conversion factor is 4.18 J/cal.

(4.18 Jg⁻¹°C⁻¹)(cal/4.18J) = 1 cal·g⁻¹°C⁻¹

First we calculate the heat required to melt the ice, where M is the mass:

Q = ML = (15 g)(80 cal/g) = 1200 cal

Then, we calculate the heat required to raise the temperature of water from 0 °C to 25 °C.

Q = mcΔt = (15 g)(1 cal·g⁻¹°C⁻¹)(25 °C - 0 °C) = 380 cal

The answer is rounded so that there are two significant figures

The total heat required for this process is (1200 cal + 380 cal) = 1580 cal

The rounded answer is 1600 calories.

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3 years ago
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