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3 years ago

Suppose △JMN≅△KQR . Which congruency statements are true?

Mathematics

2 answers:

zvonat [6]3 years ago

6 0

Answer:

<h3> $\angle M\cong\angle Q$ </h3><h3>QK $\cong$ MJ</h3><h3>MN $\cong$ QR</h3>

Step-by-step explanation:

Given $\triangle JMN\cong\triangle KQR$

Congruency means when two triangles are congruent then their corresponding sides and corresponding angles of two triangles are congruent.

Therefore, we have

$\angle J\cong \angle K$

$\angle M\cong\angle Q$

$\angle N \cong\angle R$

$JM\cong KQ$

$MN\cong QR$

$NJ\cong RK$

Hence, we can see that correct answer are

<h3> $\angle M \cong \angle Q$ </h3><h3> $QK\cong MJ$ </h3><h3> $MN\cong QR$ .</h3>

dlinn [17]3 years ago

4 0

The first , second and fourth choices are correct.

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Wat is <br><br> $3.459B<br> 2.443B<br> $55.838B<br> 85.965B <br> in dollars pls

Oksanka [162]

Answers:

$3,459,000,000

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3 years ago

The sum of a number x and 5 equals 14

pav-90 [236]

Answer:

x=9

Step-by-step explanation:

Since x+5=14, then you would subtract 5 from 14. 14-5=9. So that means x equals 9.

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3 years ago

Read 2 more answers

Solve x^2-7x+12=0 by using the quadratic formula

Katarina [22]

The answer is : x=4, 3

4 0

3 years ago

A line joins the point

Harrizon [31]

Intersection of the first two lines:

$\begin{cases}5x - 2y + 3 = 0\\4x - 3y + 1 = 0\end{cases}$

Multiply the first equation by 4 and the second by 5:

$\begin{cases}20x - 8y + 12 = 0\\20x - 15y + 5 = 0\end{cases}$

Subtract the two equations:

$(20x - 8y + 12)-(20x - 15y + 5)=0 \iff 7y+7=0 \iff y=-1$

Plug this value for y in one of the equation, for example the first:

$5x - 2\cdot (-1) + 3 = 0\iff 5x+5=0 \iff x=-1$

So, the first point of intersection is $(-1,-1)$

We can find the intersection of the other two lines in the same way: we start with

$\begin{cases}x=y\\x=3y+4\end{cases}$

Use the fact that x and y are the same to rewrite the second equation as

$x=3x+4 \iff 2x=-4 \iff x=-2$

And since x and y are the same, the second point is $(-2, -2)$

So, we're looking for a line passing through $(-1,-1)$ and $(-2, -2)$ . We may use the formula to find the equation of a line knowing two of its points, but in this case it is very clear that both points have the same coordinates, so the line must be $y=x$

In the attached figure, line $5x - 2y + 3 = 0$ is light green, line $4x - 3y + 1 = 0$ is dark green, and their intersection is point A.

Simiarly, line $x=y$ is red, line $x = 3y + 4$ is orange, and their intersection is B.

As you can see, the line connecting A and B is the red line itself.

5 0

3 years ago

Choose the inequality that represents the following graph.

zmey [24]

Answer:

(b) x ≤ -4

Step-by-step explanation:

There are a few things to note when reading an inequality on a number line.

The number line would contain the following:

i. <em>circles</em>: These can be closed or open. Closed circles are denoted by a shaded small circle showing that the point or number shown on the number line is included in the inequality. Open circles are denoted by an unshaded small circle showing that the point or number shown on the number line is not included in the range of inequality.

ii. <em>arrows</em>: An arrow can point to the right or left. When it points to the right, that means the values greater than the number specified on the number line are included in the range. When it points to the left, the values less than the number are included.

From the given number line,

The type of circle is a closed circle since it is shaded. This means that the number pointed at on the number line (-4 in this case) is included in the range.

Also, the arrow is pointing leftwards. This means that values less than the number pointed at (-4 in this case) are included in the range.

Therefore, the inequality should read,

x ≤ -4

This shows that all values of x less than or equal to -4 are included in the range.

4 0

3 years ago