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4 years ago

Please help! Correct answer only!

Mathematics

1 answer:

aksik [14]4 years ago

4 0

Answer:

0.0714

Step-by-step explanation:

The probability that the first is "working in nature" is 3/8.

The probability that the 2nd is "working in nature" is 2/7.

The probability that the 3rd is "not working in nature" is 5/6.

The probability that the 4th is "not working in nature" is 4/5.

Thus the probability that the first two of 4 opportunities are "working in nature" is ...

(3·2·5·4)/(8·7·6·5) = 1/14 ≈ 0.0714

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Later you have another chocolate bar. This time, after you give away 1/3 of the

koban [17]

Answer:

chocolate bar - 1 (whole number)

Step-by-step explanation:

$1 - \frac{1}{3} \\ > \frac{3}{3} - \frac{1}{3} = \frac{2}{3}$

$\frac{2}{3} - \frac{3}{4} \\ > \frac{2 \times 4}{3 \times 4} - \frac{3 \times 3}{4 \times 3} \\ \\ \\ > \frac{8}{12} - \frac{9}{12}$

so I switch it become

$\frac{9}{12} - \frac{8}{12} = \frac{1}{12}$

4 0

3 years ago

Solve for x. if necessary, round your answer to the nearest tenth.

frozen [14]

Answer:

Add me so when you get the equation you can ask me for help!!

Step-by-step explanation:

What is the equation

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3 years ago

Use the quadratic formula to solve x2 + 9x + 10 = 0.<br> What are the solutions to the equation?

vampirchik [111]

Answer:

$\large\boxed{x=\dfrac{-9\pm\sqrt{41}}{2}}$

Step-by-step explanation:

$\text{The quadratic formula of}$

$ax^2+bx+c=0$

$\text{If}\ b^2-4a0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\=========================================$

$\text{We have}\ x^2+9x+10=0\\\\a=1,\ b=9,\ c=10\\\\\text{substitute:}\\\\b^2-4ac=9^2-4(1)(10)=81-40=41>0\qquad _{\text{two solutions}}\\\\\sqrt{b^2-4ac}=\sqrt{41}\\\\x=\dfrac{-9\pm\sqrt{41}}{2(1)}=\dfrac{-9\pm\sqrt{41}}{2}$

5 0

3 years ago

Read 2 more answers

Chris is riding her bike for 10 miles. She averages 12 mi/h. how many more minutes must she ride before she travels 60 miles?

madam [21]

Answer:

5 Minutes

take 10 and add 12 for each minute until you pass 60

3 0

3 years ago

On a coordinate plane, a curved line with a minimum value of (1.5, negative 1) and a maximum value of (negative 1.5, 13), crosse

Arisa [49]

Answer:

Third option: (1, 0), (2, 0), and (–3, 0)

Step-by-step explanation:

The x-intercepts are the points at which the graph of the function crosses the x-axis.

By reading the question, we can see that:

"... crosses the x-axis at (negative 3, 0), (1, 0), and (2, 0)..."

So the x-intercepts are:

(-3, 0)

(1, 0)

(2, 0)

Then the correct option is the third one:

"(1, 0), (2, 0), and (–3, 0)"

7 0

3 years ago