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Dmitrij [34]
3 years ago
15

Perform the indicated operation. 5 1/6 – 2 2/3 2 1/3 2 1/2 2 1/6

Mathematics
2 answers:
Alex17521 [72]3 years ago
7 0

5 1/6 - 2 2/3

 convert to improper fractions:

5 1/6 = 31/6

2 2/3 = 8/3

find common denominator:

8/3 = 16/6

31/6 - 16/6 = 15/6

15/6 = 2 3/6 = 2 1/2

anzhelika [568]3 years ago
7 0
<span>5 1/6 – 2 2/3
= 5 1/6 - 2 4/6
= 4 7/6 - 2 4/6
= 2 3/6
= 2 1/2

answer
</span><span>2 1/2</span>
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see the attached figure to better understand the problem

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The limit of a function at a position where there is a hole in the function will exist, but the value of the function will not.

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