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liq [111]
3 years ago
10

Let C be the boundary of the region bounded by x = y4 + 1 and x = 2, oriented in anticlockwise.

Mathematics
1 answer:
murzikaleks [220]3 years ago
4 0
Assuming the first term is \dfrac{e^y}x, we have by Green's theorem,

\displaystyle\int_C\left(\frac{e^y}x\,\mathrm dx+(e^y\ln x+2x)\,\mathrm dy\right)=\iint_R\left(\dfrac\partial{\partial x}\left(e^y\ln x+2x\right)-\dfrac\partial{\partial y}\left(\frac{e^y}x\right)\right)\,\mathrm dA
=\displaystyle\int_{y=-1}^{y=1}\int_{x=y^4+1}^{x=2}\left(\frac{e^y}x+2-\frac{e^y}x\right)\,\mathrm dx\,\mathrm dy
=\displaystyle2\int_{-1}^1\int_{y^4+1}^2\,\mathrm dx\,\mathrm dy
=\displaystyle2\int_{-1}^1(1-y^4)\,\mathrm dy
=\displaystyle4\int_0^1(1-y^4)\,\mathrm dy
=\dfrac{16}5
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4 0
4 years ago
Please help me, I think this is easy but I just don't get it...
Deffense [45]

Answer:

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Step-by-step explanation:

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7 0
3 years ago
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Simplify the following square root expression of 50
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3 years ago
A satellite can move at 17,000 miles per hour. How many hours will it take to reach a star that is three light years away? Recal
babunello [35]
First convert the distance to miles 

<span>9.5 × 10^12 km x 0.62 miles/km </span>
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<span> we want to triple that, because it is 3 light years (not just 1): </span>
<span>3 x 5.9 × 10^12 miles </span>
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<span>Next divide by the speed to get the time (in hours). </span>
<span>t = 1.8 × 10^13 miles / 17000 miles/hour </span>

<span>convert the speed to scientific notation: </span>
<span>t = 1.8 × 10^13 / 1.7 x 10^4 </span>

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<span>convert that back to standard notation. </span>

<span>Answer: </span>
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4 0
4 years ago
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6 0
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