A student can take three subjects in 40 ways.
<u>SOLUTION:</u>
Given that, there are 4 different math courses, 5 different science courses, and 2 different history courses.
A student must take one of each, how many different ways can this be done?
Now, number ways to take math course = 4
Number of ways to take science course = 5
Number of ways to take history course = 2
So, now, total possible ways = product of possible ways for each course = 4 x 5 x 2 = 40 ways.
Hence, a student can take three subjects in 40 ways.
-2/3-(-1 1/3) =
-2/3 + 1 1/3 =
4/3 - 2/3 =
<em>2/3</em>
12 - (-5) =
12 + 5 =
<em>17</em>
-1 - (-6) =
-1 + 6 =
6 - 1 =
<em>5</em>
-3 3/8 - 7/8 =
27/8 - 7/8 =
20/8 =
2 4/8 =
<em>2</em><em> </em><em>1/2</em>
Answer:
6a^2
Step-by-step explanation:
Answer:
area of triangle= 1/2*h*b
= 1/2*6*16
=3*16
= 48 yd²
This is your answer. If I'm right so,
Please mark me as brainliest. thanks!!!
