<span>Traveled Downstream a distance of 33 Mi and then came right back. If the speed of the current was 12 mph and the total trip took 3 hours and 40 minutes.
Let S = boat speed in still water then (s + 12) = downstream speed (s -12) = upstream speed
Given Time = 3 hours 40 minutes = 220 minutes = (220/60) h = (11/3) h Time = Distance/Speed
33/(s +12) + 33/(s-12) = 11/3 3{33(s-12) + 33(s +12)} = 11(s+12) (s -12) 99(s -12 + s + 12) = 11(</span> s^{2} + 12 s -12 s -144) 99(2 s) = 11(s^{2} -144) 198 s/11 = (s^{2} -144) 18 s = (s^{2} -144) (s^{2} - 18 s - 144) = 0 s^{2} - 24 s + 6 s -144 =0 s(s- 24) + 6(s -24) =0 (s -24) (s + 6) = 0 s -24 = 0, s + 6 =0 s = 24, s = -6 Answer) s = 24 mph is the average speed of the boat relative to the water.
C
a ratio of 5 : 5 simplifies to 1 : 1, which basically means we require the midpoint of the line segment
using the midpoint formula
M = [
(0 + 20 ),
(15 + 0)] = (10, 7.5 )
Answer:
Surface area of the wood to be painted = (
+ r
)
- 16![\pi](https://tex.z-dn.net/?f=%5Cpi)
Step-by-step explanation:
Surface area of a cone is given as the sum of the surface area and the area of its base.
i.e Surface area = ![\pi](https://tex.z-dn.net/?f=%5Cpi)
+
Lr
where: L is the length of its slant height and r is the radius.
Applying the Pythagoras theorem,
L = ![\sqrt{h^{2} + r^{2} }](https://tex.z-dn.net/?f=%5Csqrt%7Bh%5E%7B2%7D%20%2B%20r%5E%7B2%7D%20%20%7D)
Thus,
Surface area =
r (r +
)
The given cylindrical hole has a radius of 4 cm and depth 2 cm.
The area of one of its circular surfaces = ![\pi](https://tex.z-dn.net/?f=%5Cpi)
![r^{2}](https://tex.z-dn.net/?f=r%5E%7B2%7D)
=
× ![(4)^{2}](https://tex.z-dn.net/?f=%284%29%5E%7B2%7D)
= 16
![cm^{2}](https://tex.z-dn.net/?f=cm%5E%7B2%7D)
The surface area of the piece of wood to be painted = surface area of cone - area of cylindrical circular surface.
Surface area of the wood to be painted =
r (r +
) - 16![\pi](https://tex.z-dn.net/?f=%5Cpi)
Answer:
10 + 4 i
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