Question

Not sure. Please explain the steps.

Answer 1

Answer:

C. 2x-5

Step-by-step explanation:

8x^3−10x^2−25x

4x^2+5x

=

8x^3−10x^2−25x

4x^2+5x

=

8x^2−10x−25

4x+5

=

(4x+5)(2x−5)

4x+5

=2x−5

Answer 2

Answer:

answer C

Step-by-step explanation:

hello

because this is not allowed to divide by 0 I would take x real different from 0 and from -5/4

$\dfrac{8x^3-10x^2-25x}{4x^2+5x}=\dfrac{x(8x^2-10x-25)}{x(4x+5)}=\\\dfrac{8x^2-10x-25}{4x+5}=\dfrac{(4x+5)(2x-5)}{4x+5}=2x-5$

indeed if we develop

$(4x+5)(2x-5)=8x^2-20x+10x-25=8x^2-10x-25$

hope this helps

do not hesitate if you have any question