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kozerog [31]
3 years ago
14

A 30.00 mL sample of HBr was titrated using 0.1756 M NaOH. Determine the concentration of the HBr sample if 17.52 mL of NaOH was

required to reach the endpoint in the titration.
Chemistry
1 answer:
postnew [5]3 years ago
5 0

<u>Answer:</u> The concentration of HBr sample is 0.1025 M

<u>Explanation:</u>

To calculate the concentration of acid, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is HBr

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=1\\M_1=?M\\V_1=30.00mL\\n_2=1\\M_2=0.1756M\\V_2=17.52mL

Putting values in above equation, we get:

1\times M_1\times 30.00=1\times 0.1756\times 17.52\\\\M_1=\frac{1\times 0.1756\times 17.52}{1\times 30.00}=0.1025M

Hence, the concentration of HBr sample is 0.1025 M

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Explanation:

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2 years ago
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larisa86 [58]

Answer:

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Explanation:

Step 1:

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Final temperature (T2) = 165°C

Change in temperature (ΔT) = T2 – T1 = 165°C – 10°C = 155°C

Specific heat capacity (C) =..?

Step 2:

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C = 1606 / (35 x 155)

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