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2 years ago

11.27 mol of carbon dioxide gas is equal to how many liters

Chemistry

1 answer:

saw5 [17]2 years ago

3 0

11.27 mol of carbon dioxide gas is equal to 252.45 L or 270.48 L

<h3>Further explanation</h3>

Given

11.27 mol of CO2

Required

Volume of gas

Solution

If the conditions are assumed to be at the STP state (Standard Temperature and Pressure) at T 0 ° C and P 1 atm, then Vm is 22.4 liters/mol.

so for 11.27 moles the total volume is:

11.27 mol x 22.4 L = 252.45 L

But if the conditions are assumed to be at RTP (Room Temperature and Pressure), Conditions at T 25 ° C and P 1 atm. Vm = 24 liters/mol, then the volume of CO2:

11.27 mol x 24 L = 270.48 L.

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<h3>Answer: D) all of the above</h3>

Explanation:

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2 years ago

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HELPPP!!! what is the volume (in liters) of a 5.72 gram sample of 02 at STP? (Hint: remember to change grams of oxygen to moles

Alona [7]

Answer:

Explanation:

To obtain the volume of O2 at stp, first, we need to determine the number of mole of O2.

From the question given above,

Mass of O2 = 5.72g

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Number of mole =Mass/Molar Mass

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Now, we can calculate the volume of O2 at stp as follow:

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Therefore, 0.179 mole of O2 will occupy = 0.179 x 22.4 = 4L

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2 years ago

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2 years ago

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PLEASE SOMEBODY EXPLAIN THIS :(((

djverab [1.8K]

Answer:

$\boxed{ \sf \: R_f \: value \: of \: sample \: 1 =0.3142}$

<h3>Explanation:</h3>

In Analytical Chemistry chromatography is widely used for the separation of samples.

In thin layer chromatography, the mixture of components are separated on the basis of their polarity.
The solvent solution(mobile phase) that we use are non polar & silica gel( TLC paper made of/stationary phase) are polar.
Consider the mixture we have taken consist of two samples having large polar difference.
Due to opposite nature of silica gel(polar) & solvent solution (non polar) the movement become easy & due to capillary action solvent solution rise to the top.
The mixture of sample we have taken, the sample have less polarity have high peak or they travel more distance than that of more polar sample when they dipped into the solution.

In the given diagram, mixture of 8 samples are separated on the basis of their polarity, the distance travelled by solvent is 35 mm, distance travelled by sample 1 is 11 mm & similarly distance travelled by sample 2,3,4,5,6,7 are 15,31,4,22,25,33 in mm respectively.

Rf Value: Rf value is retention factor which tells about relative absorption of each sample & range of Rf value is 0-1.

Formula to calculate Rf value is

$\sf R_f \: value = \frac{distance \: moved \: by \: sample}{distance \: moved \: by \: solvent}$

Now, solving for Rf value of sample 1

<em>Given:</em>

Distance moved by sample 1 = 11 mm

Distance movedby solvent = 35 mm

<em>To find:</em>

Rf value of sample 1 = ?

<em>Solution:</em>

Substituting the given data in above formula,

$\small \sf R_f \: value = \frac{distance \: moved \: by \: sample \: 1}{distance \: moved \: by \: solvent} \\ \small \sf R_f \: value = \cancel\frac{11 \: mm}{35 \: mm} = 0.3142$

$\small \boxed{ \sf \: R_f \: value \: of \: sample \: 1 =0.3142}$

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1 year ago