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3 years ago

How were the Great Lakes formed?

Chemistry

1 answer:

cluponka [151]3 years ago

5 0

Answer:

The Great Lakes were formed by a retreating glacier that dug out large basins. Then as the glacier melted, the water filled in those basins

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When 2-bromo-2-methylbutane is treated with a base, a mixture of 2-methyl-2-butene and 2-methyl-1-butene is produced. When potas

rjkz [21]

Answer:

The percentage mixture of 2-methyl-1-butene would be in between the 45% and 70%.

Explanation:

Potassium prop oxide is the intermediate base as compared to the potassium hydroxide which is less bulky strong base and potassium tert-butoxide which is bulky base. Bulky base can minimize the substitution reaction by causing hinders the approach of carbon attack and KOH is the strong base which less effective in minimizing the substitution reaction.

8 0

3 years ago

Among important crop plants, nitrogen-fixing root nodules are most commonly an attribute of A) corn. B) legumes. C) wheat. D) me

7nadin3 [17]

Among important crop plants, nitrogen-fixing root nodules are most commonly an attribute of
B) legumes

3 0

3 years ago

What is the study of matter and it's changes.??

kupik [55]

Physical Science is the study of matter and energy.
Physics is the study of matter, motion and energy.
Chemistry is the study of matter and its changes. Do you have an multiple choices?

5 0

3 years ago

g A gas is compressed in a cylinder from a volume of 20.0 L to 2.0 L by a constant pressure of 10.0 atm. Calculate the amount of

Lemur [1.5K]

Answer:

The amount of work done on the system is 18234 J and the final positive sign means that this work corresponds to an increase in internal energy of the gas.

Explanation:

Thermodynamic work is called the transfer of energy between the system and the environment by methods that do not depend on the difference in temperatures between the two. When a system is compressed or expanded, a thermodynamic work is produced which is called pressure-volume work (p - v).

The pressure-volume work done by a system that compresses or expands at constant pressure is given by the expression:

W system= -p*∆V

Where:

W system: Work exchanged by the system with the environment. Its unit of measure in the International System is the joule (J)
p: Pressure. Its unit of measurement in the International System is the pascal (Pa)
∆V: Volume variation (∆V = Vf - Vi). Its unit of measurement in the International System is cubic meter (m³)

In this case:

p= 10 atm= 1.013*10⁶ Pa (being 1 atm= 101325 Pa)
ΔV= 2 L- 20 L= -18 L= -0.018 m³ (being 1 L=0.001 m³)

Replacing:

W system= -1.013*10⁶ Pa* (-0.018 m³)

Solving:

W system= 18234 J

The amount of work done on the system is 18234 J and the final positive sign means that this work corresponds to an increase in internal energy of the gas.

5 0

3 years ago

what is the molar mass of a gaseous flouride of sulfur containing 70.4% F and having a density of approximately 4.5g/L at 20 deg

zlopas [31]

Answer:

The molar mass is 180.2 g/mol

Explanation:

Step 1: Data given

% of F = 70.4 %

Density = 4.5 g/L

Temperature = 20 °C

Pressure = 1 atm

Step 2: Calculate the number of moles

PV = nRT

⇒ with P = the pressure = 1.00 atm

⇒ with V = the volume = Assume this is 1L

⇒ with n = the number of moles = TO BE DETERMINED

⇒ R = the gas constant = 0.08206 L*atm/K*mol

⇒ T = the temperature : 20°C = 293 Kelvin

1 atm*1L= n(0.08206 L-atm/mol-K)*(293 K)

n = 0.04159 moles

Step 3: Calculate molar mass

Molar mass = Mass / moles

4.5 grams / 0.04159 moles = 108.2 g/mol

Step 4: Calculate moles of F

Moles = Mass / molar mass

Moles F = 70.4 g / 19 g/mol

Moles F = 3.70 moles

Moles S = 29.6g / 32.07 g/mol

Moles S = 0.923 moles S

Step 5: Divide by the smallest amount of moles

F = 3.70 / 0.923 = 4

S = 0.923 / 0.923 = 1

The empirical formula is SF4

The molar mass of SF4 = 32.07 + 4*19 = 108.07 g/mol

This means the empirical formula is the same as the molecular formula SF4

The molar mass is 180.2 g/mol

4 0

3 years ago