23 10/100 is how you would write it
Answer:
h = 61.25 m
Step-by-step explanation:
It is given that,
The initial velocity of the ball, v = 60 m/s
It is thrown from a height of 5 feet, 
We need to find the maximum height it reaches. The height reached by the projectile as a function of time t is given by :

Putting all the values,
.....(1)
For maximum height, put

Put t = 1.875 in equation (1)

So, the maximum height reached by the ball is 61.25 m.
1 x 10-3 make sure the -3 is above the 10.
-- The two sides of a right <u>angle</u> intersect and make the angle.
So do the sides of any other angle. So they can't be parallel.
-- No two sides of a right <u>triangle</u> ... or any other triangle ...can be parallel.