So even postive integers are by defention in form 2k where k is a natural number so
let the sum of even integers to n=S
S=2(1+2+3+4+5+6+7+8+......+k-1+k
divide bith sides of equation 1 by 2
0.5S=1+2+3+4+5+...........+k-1+k
S=2(k+(k-1)+..............................+2+1)
divide both sides of equation 2 by 2
0.5S=k+k-1+..............................+2+1)
by adding both we will get
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S=(k+1)(k)
so the sum will be equal to
S=

so let us test the equation
for the first 3 even number there sums will be
2+4+6=12
by our equation 3^2+3=12
gave us the same answer so our equation is correct
Answer:
91
Step-by-step explanation:
Let x be the smallest one:
● x is the first number
● x+1 is the second number
● x+2 is the third number
The sum of these numbers is 276
● x+(x+1)+(x+2) =276
● x+x+1+x+2 = 276
● 3x + 3 = 276
Substract 3 from both sides:
● 3x+3-3 = 276-3
● 3x = 273
Divide both sides by 3
● (3x)/3 = 273/3
● x = 91
So the smallest one is 91
Use Math..way. Put in equation, hit solve, will give u val. for N
Answer:
Maggie is 6 years old
Step-by-step explanation:
M + B = 26
B = 26 - M
4M - 4 = B
4M - 4 = 26 - M
5M = 30
M = 6
Maggie is 6 years old
Answer:
Sankore University
Step-by-step explanation: