636.4 is the answer. diving 5÷3182 on the caculater
Answer:
<I= 15degrees
Step-by-step explanation:
Using the cosine rule formulae;
j² = i²+k²-2i cos <J
j² = 37²+57² - 2(37)(57)cos <141
j² = 1369+ 3249- 4218cos <141
j² = 4618- 4218cos <141
j² = 4618-(-3,278)
j²= 7,896
j = √7,896
j = 88.86inches
Next is to get <I
i² = j²+k²-2jk cos <I
37² = 88.86²+57² - 2(88.86)(57)cos <I
1369 = 7,896.0996+ 3249- 10,130.04cos <I
1369 = 11,145.0996 - 10,130.04cos <I
1369 - 11,145.0996 = - 10,130.04cos <I
-9,776.0996=- 10,130.04cos <I
cos <I =9,776.0996 /10,130.04
cos<I = 0.96506
<I = 15.19
<I= 15degrees
Step-by-step explanation:
a). A = {x ∈ R I 5x-8 < 7}
5x - 8 < 7 <=> 5x < 8+7 <=> 5x < 15 =>
x < 3 => A = (-∞ ; 3)
A ∩ N = {0 ; 1 ; 2}
A - N* = (-∞ ; 3) - {1 ; 2}
b). A = { x ∈ R I 7x+2 ≤ 9}
7x+2 ≤ 9 <=> 7x ≤ 7 => x ≤ 1 => x ∈ (-∞ ; 1]
A ∩ N = {0 ; 1}
A-N* = (-∞ ; 1)
c). A = { x ∈ R I I 2x-1 I < 5}
I 2x-1 I < 5 <=> -5 ≤ 2x-1 ≤ 5 <=>
-4 ≤ 2x ≤ 6 <=> -2 ≤ x ≤ 3 => x ∈ [-2 ; 3]
A ∩ N = {0 ; 1 ; 2 ; 3}
A - N* = [-2 ; 3) - {1 ; 2}
d). A = {x ∈ R I I 6-3x I ≤ 9}
I 6-3x I ≤ 9 <=> -9 ≤ 6-3x ≤ 9 <=>
-15 ≤ -3x ≤ 3 <=> -5 ≤ -x ≤ 3 =>
-3 ≤ x ≤ 5 => x ∈ [-3 ; 5]
A ∩ N = {0 ; 1 ; 2 ; 3 ; 4 ; 5}
A - N* = [-3 ; 5) - {1 ; 2 ; 3 ; 4}
Where are the following grades ? how am i supposed to answer without all parts of the question .
