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N76 [4]
3 years ago
13

Hydrogen has three isotopes 1H, 2H, and 3H. What is the difference between these three isotopes?

Chemistry
1 answer:
ANEK [815]3 years ago
8 0
They contain different amounts of protons within them.
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6 0
3 years ago
Given the following at 25C calculate delta Hf for HCN (g) at 25C. 2NH3 (g) +3O2 (g) + 2CH4 (g) ---> 2HCN (g) + 6H2O (g) delta
AysviL [449]

<u>Answer:</u> The \Delta H_f for HCN (g) in the reaction is 135.1 kJ/mol.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. The equation used to calculate enthalpy change is of a reaction is:

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

2NH_3(g)+3O_2(g)+2CH_4(g)\rightarrow 2HCN(g)+6H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(HCN)})+(6\times \Delta H_f_{(H_2O)})]-[(2\times \Delta H_f_{(NH_3)})+(3\times \Delta H_f_{(O_2)})+(2\times \Delta H_f_{(CH_4)})]

We are given:

\Delta H_f_{(H_2O)}=-241.8kJ/mol\\\Delta H_f_{(NH_3)}=-80.3kJ/mol\\\Delta H_f_{(CH_4)}=-74.6kJ/mol\\\Delta H_f_{(O_2)}=0kJ/mol\\\Delta H_{rxn}=-870.8kJ

Putting values in above equation, we get:

-870.8=[(2\times \Delta H_f_{(HCN)})+(6\times (-241.8))]-[(2\times (-80.3))+(3\times (0))+(2\times (-74.6))]\\\\\Delta H_f_{(HCN)}=135.1kJ

Hence, the \Delta H_f for HCN (g) in the reaction is 135.1 kJ/mol.

8 0
3 years ago
Which one will diffuse faster Ammonia or carbon dioxide Why?<br><br>​
Law Incorporation [45]

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8 0
4 years ago
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PLEASE HELP ME I WILL MARK AS BRAINLIEST ANSWER-100 points
hammer [34]

Answer:

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Explanation:

5 0
3 years ago
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Backpackers often use canisters of white gas to fuel a cooking stove's burner. If one canister contains 1.45 L of white gas, and
Vaselesa [24]

The number of  kilograms  of fuel   that are contained in one  canister  is 1.03 Kilograms


calculation

mass =  density x  volume

Density= 0.710 g/cm³

volume = 1.45 L

convert  1.45 l into cm³  to make the units  uniform

that is     1 L= 1000 cm³

              1.45 L=  cm³

by cross  multiplication

= (1.45 L  x 1000 cm³)  / 1 L  = 1450 cm³


mass is therefore =   0.710g/cm³  x 1450 cm³   =1029.5 grams


convert grams to Kg

1 kg = 1000 grams

  ? kg  =1029.5  grams

by cross  multiplication

= (1 kg  x 1029.5 grams) /1000 grams  = 1.0295 Kg ≅1.03 kg



7 0
4 years ago
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