How do scientists determine the number of neutrons in an isotope of an atom
2 answers:
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Answer : The incorrect option is, (d)
Explanation :
According to the Bronsted Lowry concept, Bronsted Lowry-acid is a substance that donates one or more hydrogen ion in a reaction and Bronsted Lowry-base is a substance that accepts one or more hydrogen ion in a reaction.
Or we can say that, conjugate acid is proton donor and conjugate base is proton acceptor.
(a) The equilibrium reaction will be,
In this reaction, is an acid that donate a proton or hydrogen to
base and it forms
and
are conjugate base and acid respectively.
In this reaction, are act as a conjugate acid-base.
(b) The equilibrium reaction will be,
In this reaction, is an acid that donate a proton or hydrogen to
base and it forms
and
are conjugate base and acid respectively.
In this reaction, are act as a conjugate acid-base.
(c) The equilibrium reaction will be,
In this reaction, is an acid that donate a proton or hydrogen to
In this reaction, are act as a conjugate acid-base.
(d) The equilibrium reaction will be,
In this reaction, is an acid that donate a proton or hydrogen to
base and it forms
and
are conjugate base and acid respectively.
In this reaction, are act as a conjugate acid-base.
(e) The equilibrium reaction will be,
In this reaction, is an acid that donate a proton or hydrogen to
base and it forms
In this reaction, are act as a conjugate acid-base.
From this we conclude that that, pairs of acids and conjugate bases is incorrectly labeled or incorrectly matched.
Hence, the incorrect option is, (d)
<u>Answer:</u> The of the reaction is
<u>Explanation:</u>
For the given half reactions:
Oxidation half reaction:
Reduction half reaction:
Net reaction:
Oxidation reaction occurs at anode and reduction reaction occurs at cathode.
To calculate the of the reaction, we use the equation:
Putting values in above equation, we get:
To calculate equilibrium constant, we use the relation between Gibbs free energy, which is:
and,
Equating these two equations, we get:
where,
n = number of electrons transferred = 2
F = Faraday's constant = 96500 C
= standard electrode potential of the cell = 0.48 V
R = Gas constant = 8.314 J/K.mol
T = temperature of the reaction =
= equilibrium constant of the reaction = ?
Putting values in above equation, we get:
Hence, the of the reaction is