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vfiekz [6]
3 years ago
8

60 points please help me i will appreciate it!

Chemistry
1 answer:
Setler79 [48]3 years ago
4 0

Answer:

\huge\boxed{\sf T = 682.4 \ K}

Explanation:

<u>Given Data:</u>

Mole = n = 0.1 mol

Pressure = P = 530 mmHg = 0.7 atm

Volume = v = 8 L

Ideal gas constant = R = 0.8206 L atm K⁻¹ mol⁻¹

<u>Required:</u>

Temperature = T = ?

<u>Formula:</u>

Pv = nRT

<u>Solution:</u>

Rearranging for T

     \displaystyle T = \frac{Pv}{nR} \\\\T = \frac{(0.7)(8)}{(0.1)(0.08206)} \\\\T = \frac{5.6}{0.008206} \\\\T = 682.4 \ K\\\\\rule[225]{225}{2}

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<u>Answer:</u> The given chemical reaction can be classified as synthesis and exothermic.

<u>Explanation:</u>

A synthesis reaction is defined as the reaction where two small chemical species combine in their elemental state to form a single large chemical species.

Exothermic reactions are defined as the reactions in which heat is released by the reaction. The heat is written on the product side of the reaction.

For the given chemical reaction:

Mg(s)+O_2(g)\rightarrow MgO(s)+\text{heat}

The above chemical reaction is a type of synthesis and exothermic as two substances in their elemental state are combining. Also, heat is getting released in the reaction.

Hence, the given chemical reaction can be classified as synthesis and exothermic.

4 0
3 years ago
Help asap!!!!!!!!!!!
ivann1987 [24]
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3 0
3 years ago
The standard free energy of activation of one reaction A is 95.00 kJ mol–1 (22.71 kcal mol–1). The standard free energy of activ
diamong [38]

Answer:

The answer to the questions are as follows

Reaction B is 4426.28 times faster than reaction A

(b) Reaction B is faster.

Explanation:

To solve the question we are meant to compare both reactions to see which one is faster

The values of the given activation energies are as follows

For A

Ea = 95.00 kJ mol–1 (22.71 kcal mol–1) and

for  B

Ea = 74.20 kJ mol–1 (17.73 kcal mol–1)

T is the same for both reactions and is equal to 298 k

Concentration of both reaction = 1M

The Arrhenius Law is given by

k = Ae^{\frac{-E_{a} }{RT} }

Where

k = rate constant

Ea = activation energy

R = universal gas constant

T = temperature  (Kelvin )

A = Arrhenius factor

Therefore

For reaction A, the rate constant k₁ is given by k₁ = Ae^{\frac{-95000}{(8.314)(298)} }

And for B the rate constant k₂ is given by k₂ = Ae^{\frac{-74200 }{(8.314)(298)} }

k₁ = A×2.225×10⁻¹⁷

k₂ = A×9.850×10⁻¹⁴

As seen from the above Reaction B is faster than reaction A by (A×9.850×10⁻¹⁴)/(A×2.225×10⁻¹⁷) or 4426.28 times

3 0
3 years ago
The exhaust gas from an automobile contains 1.5 percent by volume of carbon monoxide. What is the concentration of CO in mg/m' a
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Answer:

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(b) 11,625 mg/m3

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The concentration of CO in mg/m3 can be calculated as

C (mg/m3) =(P/RT)*MW*C_{ppm}

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Then the concentration in mg/m3 is

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Answer:

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