All categories

3 years ago

If AJKL = AMNP, which statement must be true?

Mathematics

2 answers:

Karo-lina-s [1.5K]3 years ago

7 0

Where are the statements

gavmur [86]3 years ago

4 0

Aj=am and kl=np but i need the original statements

You might be interested in

PLZ HELP WILL MARK BRANLIEST (No dum answers or I will delete your question - seriously don't be annoying)

Vsevolod [243]

Answer:

A. tan(2π/3) = $-\sqrt{3}$

4 0

2 years ago

Cora babysat for 3 1/2 hours and charged at $28. At the same hourly rate, what would she charge for 5 1/2 hours of babysitting?

RUDIKE [14]

42.9 goodluck :) ...

7 0

3 years ago

A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect

Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

$P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99$

Compute the probability that a person does not have the disease as follows:

$P(D^{c})=1-P(D)=1-0.88=0.12$

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

$P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264$

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

$P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188$

Compute the probability that a randomly selected person is tested negative as follows:

$P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})$

$=0.0264+0.1188\\=0.1452$

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0

3 years ago

Which function represents by the table

andreev551 [17]

F(x)= 4x this is because everything is times 4

3 0

1 year ago

What is the square root of 5 divided by the square root of 15 and simplify and in fraction form

ozzi

Answer:

$\sqrt{\frac{1}{3} }$

$\frac{\sqrt{3} }{3}$

Step-by-step explanation:

The expression $\frac{\sqrt{5} }{\sqrt{15} }$ can be simplified by first writing the fraction under one single radical instead of two.

$\frac{\sqrt{5} }{\sqrt{15} } = \sqrt{\frac{5}{15} }$

5/15 simplifies because both share the same factor 5.

It becomes $\sqrt{\frac{5}{15} } = \sqrt{\frac{1}{3} }$

This can simplify further by breaking apart the radical.

$\sqrt{\frac{1}{3} } = \frac{\sqrt{1} }{\sqrt{3} } = \frac{1}{\sqrt{3} }$

A radical cannot be left in the denominator, so rationalize it by multiplying by √3 to numerator and denominator.

$\frac{1}{\sqrt{3} } *\frac{\sqrt{3} }{\sqrt{3} } =\frac{\sqrt{3} }{3}$

4 0

3 years ago