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Kisachek [45]
4 years ago
5

Please help meeeeee with this

Mathematics
1 answer:
aleksandrvk [35]4 years ago
8 0
Alright, let's do all of these (though this is a bit long).
1.
The constant is 1.8. All other values are coefficients to variables, which as the name implies will change.
2.
1 hour is 60 minutes, 1 minute is 60 seconds.
So, 4.2 *60 *60 = 15120 seconds.
3.
<span>−5x−4(x−6)=−3-5x-4(x-6)=-3
Let's move all x to one side, and all other numbers to another.
-5x-4(x-6)=-3-5x-4(x-6)=-3
x can be any value you want, if you actually solve this you'll only end up with -3 = -3, which is correct, of course.
Let me show you:
</span><span>−5x−4(x−6)=−3-5x-4(x-6)=-3
+5x +4(x-6)        +5x +4(x-6)
-3 = -3
The value of x is irrelevant, then. X can be any real number.
4.
I'm going to assume it was an error in printing with this? If not please correct me.
m=a+2b(or b2)
subtract 2b from each
a=m-2b
(This question seems kind of odd. We should probably address this in the comments.)
5.
</span><span>5(x−2)<−3x+6
Move all x to one side, numbers to other.
5x-10<-3x+6
+3x     +3x
    +10      +10
8x<16
/8
<span>x < 2
</span>6.
y-3=3(x-5)
alright, to find zeros set one variable to zero and solve
x first
-3=3x-15
+15    +15
3x=12
/3
x=4
x-int is (4,0)
now y
</span>y-3=3(0-5)
y-3=-15
+3     +3
y=-12
so y-int is (0,-12)
i've got to sleep now so i'll do the rest tomorrow. Sorry for the incomplete answer.

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Some money is shared between erin, faye and sachin in the ratio 5:2:7. Faye gets £90 less than sachin. How much money did Erin g
VARVARA [1.3K]

Answer:

Erin gets £90

Step-by-step explanation:

Ratio = 5 : 2 : 7

Money with Erin = 5x

Money with Faye = 2x

Money with Sachin = 7x

Faye gets £90 less than Sachin

7x -  2x = 90

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The sales decay for a product is given by S = 70000e^ -0.8x where S is the monthly sales and x is the number of months that have
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Answer:

After 5.31 months sales will drop below 1000 and 5 months after the end of the campaign sales will be 1282.09

Step-by-step explanation:

Let's find the solutions for the two questions.

First question: How many months after the end of the campaign will sales drop below 1000.

Because the problem asks for how many months, and since 'x' represents month variable, then the problem is asking for 'x'.

Using the same equation for sales we can observe the following:

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1000/70000=e^{-0.8X} which is equal to:

1/70=e^{-0.8X} by applying ln(x) properties:

ln(1/70)=ln(e^{-0.8X}) which is equal to:

ln(1/70)=-0.8X which is equal to:

ln(1/70)/(-0.8)=X so:

X=5.31 months

Second question: what will be the sales 5 months after the end of the campaign.

Because the problem asks for what will be the sales, and since 'S' represents the sales, then the problem is asking for 'S'.

Using the same equation for sales we can observe the following:

S=70000*e^{-0.8X}, but we have x which is 5 months, so:

S=70000*e^{-0.8*5} which is equal to

S=1282.09

In conclusion, after 5.31 months sales will drop below 1000 and 5 months after the end of the campaign sales will be 1282.09.

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