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lyudmila [28]
3 years ago
9

Frank worked 8 hours on the first four days of the week. How many hours did he work in these four days?

Mathematics
1 answer:
Setler [38]3 years ago
4 0

Answer:

8 hours

Step-by-step explanation:


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The first element in an arithmetic sequence is 2. Its twenty second is 14. Find the value of n so that a(n)=6
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<h2>n = 8</h2>

Step-by-step explanation:

Given the nth term of an arithmetic sequence to be Tn = a+(n-1)d

a = first term of the sequence

n = number of terms

d = common difference.

Given the first element a = 2 and 22nd to be 14

T22 = a+(22-1)d = 14

a+21d = 14

Substtuting a = 2 into the equation to get d

2+21d = 14

21d = 12

d = 12/21

d = 4/7

The nth term of the sequence given a = 2 and d = 4/7 will be expressed as;

Tn = 2+(n-1)4/7

Given Tn = 6

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6 = 2+4/7 n - 4/7

6-2+4/7 = 4/7 n

32/7=4/7 n

32 = 4n

n = 32/4

n = 8

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3 years ago
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Step-by-step explanation:

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