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2 years ago

Which is the equation of the given line in point-slope form?

Mathematics

1 answer:

Kitty [74]2 years ago

3 0

Answer:

y-8=-1×(x+0)

Step-by-step explanation:

m=y2-y1/x2-x1

m=0-(8)/8-(0)

m=-8/8-(0)

m=-8/8+0

m=-8/8

m=-1

y-(8)=-1×(x-(0))

y-8=-1×(x+0)

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Please help!! x = 2 - 3 cos t, y = 1 + 4 sin t in rectangular form?<br><br> thank you! :)

sukhopar [10]

Answer:

$\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1$

Step-by-step explanation:

$x=2-3\cos(t)$

$y=1+4\sin(t)$

Let's solve for $\cos(t)$ in the first equation and then solve for $\sin(t)$ in the second equation.

I will then use the following identity to get right of the parameter, $t$ :

$\cos^2(t)+\sin^2(t)=1$ (Pythagorean Identity).

Let's begin with $x=2-3\cos(t)$ .

Subtract 2 on both sides:

$x-2=-3\cos(t)$

Divide both sides by -3:

$\frac{x-2}{-3}=\cos(t)$

Now time for the second equation, $y=1+4\sin(t)$ .

Subtract 1 on both sides:

$y-1=4\sin(t)$

Divide both sides by 4:

$\frac{y-1}{4}=\sin(t)$

Now let's plug it into our Pythagorean Identity:

$\cos^2(t)+\sin^2(t)=1$

$\frac{x-2}{-3})^2+(\frac{y-1}{4})^2=1$

$\frac{(x-2)^2}{(-3)^2}+\frac{(y-1)^2}{4^2}=1$

$\frac{(x-2)^2}{9}+\frac{(y-1)^2}{16}=1$

5 0

2 years ago

Read 2 more answers

3=x+9<br> PLEASE SHOW WORK. SOLVE AND CHECK.

Vika [28.1K]

Answer:

x = —6

Step-by-step explanation:

3 = x + 9

Collect like terms

3 — 9 = x

— 6 = x

x = —6

4 0

2 years ago

If h(x) = (f o g)(x) and h(x) = sqrt(x+5), find g(x) if f(x) = sqrt(x+2)

agasfer [191]

Answer:

g(x) = x + 3

Step-by-step explanation:

<h3>Given</h3>

h(x) = (f ο g)(x)
h(x) = $\sqrt{x+5}$
f(x) = $\sqrt{x+2}$

g(x)

<h3>Solution</h3>

(f ο g)(x) = f(g(x))

<u>Substitute x with g(x) and solve for g(x):</u>

$\sqrt{x+5}$ = $\sqrt{g(x)+2}$
x + 5 = g(x) + 2
x + 3 = g(x)
g(x) = x + 3

7 0

2 years ago

For a pair of similar triangles, corresponding sides are always congruent.<br> True or false?

baherus [9]

That's false.
For similar triangles, corresponding angles are congruent.
Corresponding sides are in the same ratio but rarely congruent.
(They're congruent only if the ratio is ' 1 ', i.e. the triangles are congruent
as well as being similar.)

6 0

3 years ago

Read 2 more answers

Help plzzzzzzzzz????? asapp

Fiesta28 [93]

The two angles are a linear pair.
(Explanations down below!)

Linear pair angles must add up to 180 degrees. You can tell that the two angles add up to 180 degrees because they form a straight line (which is 180 degrees).

Complementary angles add up to 90 degrees. The two angles are not complementary because they do not form a 90 degree angle (right triangle, square in corner, like a L shape).

Vertical angles are opposite each other and are equal to one another. These angles are adjacent to each other and do not look similar.

6 0

2 years ago