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ad-work [718]
3 years ago
6

Find sin x/2, cos x/2, and tan x/2 from the given information.. cos x = −15/17, 180° < x < 270°. . sin x/2=. . cos x/2=. .

tan x/2=
Mathematics
2 answers:
sukhopar [10]3 years ago
6 0
So base on your question the possible answer to that kind of question and the solution are the following and i hope you will understand the formula and free to ask some questions if needed.

<span>2<span>cos2</span><span>x2</span>=1+cosx=1−<span>1517</span>=<span>217</span>,<span>cos2</span><span>x2</span>=<span>117</span></span> <span>cos<span>x2</span>=−<span>1<span>17<span>−−</span>√</span></span>....(1)</span> <span>sin<span>x2</span>=<span>1<span>17<span>−−</span>√</span></span>,90<<span>x2</span><135</span> <span>sin<span>x2</span>>0,cos<span>x2</span><0,tan<span>x2</span><0</span> <span>2<span>sin2</span><span>x2</span>=1−cosx=1−<span><span>−15</span>17</span>=<span>3217</span>,sin<span>x2</span>=<span>4<span>17<span>−−</span>√</span></span>.....(2)</span><span> divide (2) by (1) and get the value of tan x/2</span>
EleoNora [17]3 years ago
3 0

\rm sin\dfrac{1}{2}x=\sqrt{ \dfrac{32}{54}}\\\\cos\dfrac{1}{2}x=-\sqrt{ \dfrac{2}{54} }\\\\tan\dfrac{1}{2}x=-4

<h3>Further explanation </h3>

Trigonometry is the science of mathematics that studies the relationship between sides and angles in triangles

In a cartesian plane, the angle α can vary from 0 ° to 360 °, counterclockwise

This coordinate field is divided into 4 quadrants:

  • quadrant 1: 0 ° - 90 °
  • quadrant 2: 90 ° - 180 °
  • quadrant 3: 180 ° - 270 °
  • quadrant 4: 270 ° - 360 °

For half angle we can find it from double angle

Trigonometry Formulas for Double Angles:

sin 2A = 2 sin A cos A

cos 2A = 1 - 2 sin²A = 2cos²A-1

tan 2A = 2 tan A / 1-tan²A

then:

cos 2A = 2cos²A-1

\rm cos\:A=2cos^2\dfrac{1}{2}A-1\\\\2cos^2\frac{1}{2}A=1+cos\:A\\\\cos^2\frac{1}{2}A=\dfrac{1+cos\:A}{2}\\\\cos\:\frac{1}{2}A=\sqrt{\dfrac{1+cos\:A}{2} }

cos 2A = 1-2 sin²A

in the same way

\rm sin\dfrac{1}{2}A=\sqrt{\dfrac{1-cos\:A}{2} }

\rm tan\dfrac {1} {2}A = \sqrt {\dfrac {1-cos\:A} {1+cos\:A}}

input the value : cos x = −15/17

Because x in the quadrant III (180° < x < 270°) , then

  \rm \dfrac{1}{2}x\Rightarrow quadrant\:II

For quadrant I, only sin have positif value, for cos and tan have negatif value

\rm sin\dfrac{1}{2}x=\sqrt{\dfrac{1-cos\:x}{2} }

\rm sin\dfrac{1}{2}x=\sqrt{\dfrac{1-(-\dfrac{15}{17}) }{2} }\\\\sin\dfrac{1}{2}x=\sqrt{\dfrac{1\dfrac{15}{17} }{2} }=\sqrt{\dfrac{32}{54} }

\rm cos\:\frac{1}{2}x=-\sqrt{\dfrac{1+cos\:x}{2} }\\\\cos\:\frac{1}{2}x=-\sqrt{\dfrac{1-\dfrac{15}{17} }{2} }=-\sqrt{\dfrac{2}{54} }

\rm tan\dfrac {1} {2}x = -\sqrt {\dfrac {1-cos\:x} {1+cos\:x}}\\\\tan\dfrac {1} {2}x = -\sqrt {\dfrac {1+\frac{15}{17} } {1-\frac{15}{17} }}\\\\tan\dfrac{1}{2}x=-\sqrt{\dfrac{\dfrac{32}{17}}{\dfrac{2}{17} } }=-\sqrt{16}=-4

<h3>Learn more </h3>

trigonometric ratio

brainly.com/question/9880052

Prove the converse of the Pythagorean Theorem

brainly.com/question/1597216

Use Pythagoras' theorem

brainly.com/question/10488367

the triangle angle  

brainly.com/question/1611320

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