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3 years ago

Which division problem is equivalent to 38 38 ?

Mathematics

1 answer:

emmasim [6.3K]3 years ago

7 0

Just cut that, and do half of it.

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PLEASE HELP OUT!!! im super lost.

Alex73 [517]

Just replace X with the given value.

X = -3

f(-3) = 5 - (-3)

f(-3) = 5 +3

f(-3) = 8

3 0

2 years ago

What does 3 and 16 go into 10,100 or 1,000

lesya692 [45]

I think they both go into 10,000 bases of the calculations from the calculator on my phone

7 0

2 years ago

1. MONDAY (5/18): Which of the following functions matches the graph to the right

Strike441 [17]

Answer:

a.) f(x) = -⅙(x+3)²+6

Step-by-step explanation:

The maximum value, our vertex, is at point (-3,6).

We can insert this value into the vertex form of a quadratic function and then solve for a as follows...

$4.5 = a(0 +3)^2 +6\\4.5=a(9)+6\\-1.5 = 9a \\-.17=a\\a = -1/6$

a equals -1/6... We can input this into the original equation we used...

f(x) = -1/6(x+3)^2+6

Good luck on the bellwork ;)

7 0

2 years ago

Hi can you please help me with my work

LekaFEV [45]

The answer is 5 3/8”

7 0

2 years ago

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm. The area of printed material on the po

grin007 [14]

Answer:

Dimensions of printed poster are

length is 32 cm

width is 48 cm

Step-by-step explanation:

Let's assume

length of printed poster is x cm

width of printed poster is y cm

now, we can find area of printed poster

so, area of printed poster is

$=xy$

we are given that area as 1536

so, we can set it to 1536

$xy=1536$

now, we can solve for y

$y=\frac{1536}{x}$

now, we are given

The top and bottom margins of a poster are each 12 cm and the side margins are each 8 cm

so, total area of poster is

$A=(8+x+8)\times (12+y+12)$

$A=(x+16)\times (y+24)$

now, we can plug back y

$A=(x+16)\times (\frac{1536}{x}+24)$

now, we have to minimize A

so, we will find derivative

$A'=\frac{d}{dx}\left(\left(x+16\right)\left(\frac{1536}{x}+24\right)\right)$

we can use product rule

$A'=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)$

$=\frac{d}{dx}\left(x+16\right)\left(\frac{1536}{x}+24\right)+\frac{d}{dx}\left(\frac{1536}{x}+24\right)\left(x+16\right)$

now, we can simplify it

$A'=-\frac{24576}{x^2}+24$

now, we can set it to 0

and then we can solve for x

$A'=-\frac{24576}{x^2}+24=0$

$-\frac{24576}{x^2}x^2+24x^2=0\cdot \:x^2$

$-24576+24x^2=0$

$x=32,\:x=-32$

Since, x is dimension

and dimension can never be negative

so, we will only consider positive value

$x=32$

now, we can solve for y

$y=\frac{1536}{32}$

$y=48$

so, dimensions of printed poster are

length is 32 cm

width is 48 cm

5 0

2 years ago