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3 years ago

There are 269 basketball

Mathematics

2 answers:

Vesna [10]3 years ago

8 0

Simple division. 269/48=5.60416666667. You probably cannot put decimals, so round to 6.

Vilka [71]3 years ago

3 0

It’s 48r5 hopefully it helps

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Find (g o f)(-1). *

klio [65]

Answer:

D -9

Step-by-step explanation:

(g o f)(-1) = g(f(-1))

f(-1) = $f(-1) = (-1)^{2} + 2(-1) - 3\\= 1 - 2 - 3\\= -4$

g(-4) = -4 - 5 = -9

So, (g o f)(-1) = -9

6 0

3 years ago

A rectangular field with one side along a river is to be fenced. Suppose that no fence is needed along the river, the fence on t

Andreas93 [3]

Answer:

a) Side Parallel to the river: 200 ft

b) Each of the other sides: 400 ft

Step-by-step explanation:

Let L represent side parallel to the river and W represent width of fence.

The required fencing (F) would be $F=L+2W$ .

We have been given that field must contain 80,000 square feet. This means area of field must be equal to 80,000.

$LW=80,000...(1)$

We are told that the fence on the side opposite the river costs $20 per foot, and the fence on the other sides costs $5 per foot, so total cost (C) of fencing would be $C=20L+5(2W)\Rightarrow 20L+10W$ .

From equation (1), we will get:

$L=\frac{80,000}{W}$

Upon substituting this value in cost equation, we will get:

$C=20(\frac{80,000}{W})+10W$

$C=\frac{1600,000}{W}+10W$

$C=1600,000W^{-1}+10W$

To minimize the cost, we need to find critical points of the the derivative of cost function as:

$C'=-1600,000W^{-2}+10$

$-1600,000W^{-2}+10=0$

$-1600,000W^{-2}=-10$

$-\frac{1600,000}{W^2}=-10$

$-10W^2=-1,600,000$

$W^2=160,000$

$\sqrt{W^2}=\pm\sqrt{160,000}$

$W=\pm 400$

Since width cannot be negative, therefore, the width of the fencing would be 400 feet.

Now, we will find the 2nd derivative as:

$C''=-2(-1600,000)W^{-3}$

$C''=3200,000W^{-3}$

$C''=\frac{3200,000}{W^3}$

Now, we will substitute $W=400$ in 2nd derivative as:

$C''(400)=\frac{3200,000}{400^3}=\frac{3200,000}{64000000}=0.05$

Since 2nd derivative is positive at $W=400$ , therefore, width of 400 ft of the fencing will minimize the cost.

Upon substituting $W=400$ in $L=\frac{80,000}{W}$ , we will get:

$L=\frac{80,000}{400}\\\\L=200$

Therefore, the side parallel to the river will be 200 feet.

4 0

3 years ago

Triangle MNP has vertices N(2, 2) and P(0, –2). The triangle is symmetric about the y-axis. What is the approximate measure of t

Evgesh-ka [11]

Point M of the triangle is (-2,2) to make triangle MNP as shown in the attached image

Triangle MNP has a base of 4 units and a height of 4 units. We can work out the angle x and angle y using trigonometry ratio

We use tan ratio to find both angles

$Tan (x) = \frac{opposite}{adjacent}$
$Tan(x)= \frac{4}{2}$
$Tan(x)=2$
$Tan^{-1}(2)=63.43494882$
$Angle x=63.43$

$Tan(y)= \frac{opposite}{adjacent}$
$Tan(y)= \frac{2}{4}$
$Tan^{-1}(0.5)=26.56505118$
$Angle y=26.6$

Angle MNP = Angle NMP = 63.43 degrees (this is based on the fact that the triangle is an isosceles triangle)

Angle MPN = 2×26.6 = 53.2 degrees (we multiply by 2 as angle y is only a half of angle MPN - as shown in the diagram)