Explanation:
The given data is as follows.
Electric field strength (E) = 187,500 V/m
Magnetic field strength (B) = 0.125 T
Diameter (d) = 25.05 cm = 0.2505 m (as 1 m = 100 cm)
Radius (r) =
=
= 0.12525 m
Formula to calculate the magnetic force () is as follows.
............ (1)
Electrical force is calculated as follows.
............ (2)
On both electric and magnetic fields the velocity is perpendicular.
= 0
or,
Hence, from equations (1) and (2)
Bqv = qE
or, v = ............. (3)
=
= 1,500,000 m/s
As the particle is moving in a semi-circular trajectory and motion of charged particle is given by the electric field as follows.
........... (4)
where, = centripetal force
Using equation (1) and (4) as follows.
Bqv =
=
=
Thus, we can conclude that charge-to-mass ratio of the given particle is .
