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Ugo [173]
3 years ago
6

If you are building a clock by using a pendulum's oscillations to keep time and you find the period is a little too small (the c

lock counts seconds too quickly), what should you do to adjust the pendulum's period? O
a. Increase the length of the string
b. Increase the mass on the end of the string
c. Increase the amplitude of the swing
d. Decrease the length of the string
e. Decrease the mass on the end of the string
Physics
1 answer:
Leviafan [203]3 years ago
3 0

Time period of pendulum is given by

T = 2\pi\sqrt{\frac{L}{g}}

Here,

L is length

g is acceleration due to gravity

Therefore we can determine that the period of the pendulum is directly proportional to the square root of the length of the rope.

T \propto \sqrt{L}

Therefore, it is necessary to increase the length of the rope to increase the period so that it counts the seconds more slowly. The correct answer is A.

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A jet is travelling at a speed of 1200 km/h and drops cargo from a height of 2.5 km above the ground Calculate the time it takes
OLEGan [10]

a) Time of flight: 22.6 s

To calculate the time it takes for the cargo to reach the ground, we just consider the vertical motion of the cargo.

The vertical position at time t is given by

y(t) = h +u_y t - \frac{1}{2}gt^2

where

h = 2.5 km = 2500 m is the initial height

u_y = 0 is the initial vertical velocity of the cargo

g = 9.8 m/s^2 is the acceleration of gravity

The cargo reaches the ground when

y(t) = 0

So substituting it into the equation and solving for t, we find the time of flight of the cargo:

0 = h - \frac{1}{2}gt^2\\t=\sqrt{\frac{2h}{g}}=\sqrt{\frac{2(2500)}{9.8}}=22.6 s

b) 7.5 km

The range travelled by the cargo can be calculated by considering its horizontal motion only. In fact, the horizontal motion is a uniform motion, with constant velocity equal to the initial velocity of the jet:

v_x = 1200 km/h \cdot \frac{1000 m/km}{3600 s/h}=333.3 m/s

So the horizontal distance travelled is

d=v_x t

And if we substitute the time of flight,

t = 22.6 s

We find the range of the cargo:

d=(333.3)(22.6)=7533 m = 7.5 km

7 0
3 years ago
The speed of a sound wave traveling through air is 400 meters per second. The wavelength of the wave is 25 meters What is the
sweet [91]

Answer:

16Hz

Explanation:

Given parameters:

Speed of sound  = 400m/s

Wavelength  = 25m

Unknown:

Frequency of the wave  = ?

Solution:

To solve this problem;

      V  = F ∧  

V is the velocity

F is the frequency

∧ is the wavelength

      400  = F x 25

        F  = 16Hz

7 0
3 years ago
Read 2 more answers
A robot standing on a cliff shoots a ball upwards with an initial speed of 30 m/s. What is the height of the cliff given that th
valina [46]

Answer:

C 80 m

Explanation:

Given:

v₀ = 30 m/s

a = -10 m/s²

t = 8 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (30 m/s) (8 s) + ½ (-10 m/s²) (8 s)²

Δy = -80 m

The ball lands 80 m below where it started.  So the height of the cliff is 80 m.

5 0
3 years ago
What’s the transmission of heat requiring the movement of a liquid or a gas is?
-BARSIC- [3]
Convection is the answer i
think 
6 0
3 years ago
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PLS HELP ME, 40 POINTS PLUS BRAINLIEST
bulgar [2K]

Answer:

there is no question

Explanation:

5 0
3 years ago
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