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Ugo [173]
3 years ago
6

If you are building a clock by using a pendulum's oscillations to keep time and you find the period is a little too small (the c

lock counts seconds too quickly), what should you do to adjust the pendulum's period? O
a. Increase the length of the string
b. Increase the mass on the end of the string
c. Increase the amplitude of the swing
d. Decrease the length of the string
e. Decrease the mass on the end of the string
Physics
1 answer:
Leviafan [203]3 years ago
3 0

Time period of pendulum is given by

T = 2\pi\sqrt{\frac{L}{g}}

Here,

L is length

g is acceleration due to gravity

Therefore we can determine that the period of the pendulum is directly proportional to the square root of the length of the rope.

T \propto \sqrt{L}

Therefore, it is necessary to increase the length of the rope to increase the period so that it counts the seconds more slowly. The correct answer is A.

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A 3000-N force gives an object an acceleration of 15 m/s2. The mass of the object is
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<h3>Answer:</h3>

200 kg

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Physics</u>

<u>Newton's Law of Motions </u>

Newton's 1st Law of Motion: An object at rest remains at rest and an object in motion stays in motion

Newton's 2nd Law of Motion: F = ma (Force is equal to [constant] mass times acceleration)

Newton's 3rd Law of Motion: For every action, there is an equal and opposite reaction<u> </u>

<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] F = 3000 N

[Given] a = 15 m/s²

[Solve] m = <em>x</em> kg

<u>Step 2: Solve for </u><em><u>m</u></em>

  1. Substitute in variables [Newton's Second Law of Motion]:                          3000 N = m(15 m/s²)
  2. [Mass] [Division Property of Equality] Isolate <em>m</em> [Cancel out units]:            200 kg = m
  3. [Mass] Rewrite:                                                                                               m = 200 kg
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