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Ugo [173]
3 years ago
6

If you are building a clock by using a pendulum's oscillations to keep time and you find the period is a little too small (the c

lock counts seconds too quickly), what should you do to adjust the pendulum's period? O
a. Increase the length of the string
b. Increase the mass on the end of the string
c. Increase the amplitude of the swing
d. Decrease the length of the string
e. Decrease the mass on the end of the string
Physics
1 answer:
Leviafan [203]3 years ago
3 0

Time period of pendulum is given by

T = 2\pi\sqrt{\frac{L}{g}}

Here,

L is length

g is acceleration due to gravity

Therefore we can determine that the period of the pendulum is directly proportional to the square root of the length of the rope.

T \propto \sqrt{L}

Therefore, it is necessary to increase the length of the rope to increase the period so that it counts the seconds more slowly. The correct answer is A.

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A 22.0 kg child slides down a slide that makes a 37.0° angle with the horizontal. (a) What is the magnitude of the normal force
patriot [66]

Answer:

(a) 172.185 N

(b) 53^{\circ}

Solution:

As per the question:

Mass of the child, m = 22.0 kg

Angle, \theta = 37.0^{\circ}

Now,

(a) The magnitude of the normal force exerted by the slide on the child:

F_{N} = mgcos\theta

F_{N} = 22\times 9.8cos37^{\circ} = 172.185\ N

Now,

(b) The angle from the horizontal at which the force is directed is:

90^{\circ} - 37^{\circ} = 53^{\circ}

6 0
3 years ago
Janet wants to find the spring constant of a given spring, so she hangs the spring vertically and attaches a 0.40 kg mass to the
Aleks [24]

Answer:

Explanation:

mg = kx

k = mg/x

k = 0.40(9.8)/0.030

k = 130.66666...

k ≈ 130 N/m

4 0
3 years ago
The human ear canal is about 2.3 cm long. If it is regarded as a tube open at one end and closed at the eardrum, what is the fun
mariarad [96]

Answer:

For the given conditions the fundamental frequency is 3728.26 Hertz

Explanation:

We know that for a pipe open at one end and closed at other end the fundamental frequency is given by

f=\frac{V_{s}}{4L}

where

f is the fundamental frequency

V_{s} is the speed of sound in air in the surrounding conditions.

L = Length of the pipe

Applying values we get and using speed of sound as 343m/s we get

f=\frac{343}{4\times 2.3\times 10^{-2}}=3728.26Hz

7 0
3 years ago
If the density of an object is 5.2 g/cm3, and volume is 3.7 cm3, what is its mass
netineya [11]
Here's the equation you use: Density = mass/volume

1) 5.2g/cm^3 = m/3.7cm^3

2) m = 5.2g/cm^3 x 3.7cm^3

3) m = 19.24g

You can check the answer by plugging it in

19.24g/3.7cm^3
= 5.2g/cm^3
6 0
3 years ago
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Answer:

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Explanation:

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