Answer : The concentration of the NaOH solution is, 0.738 M
Explanation :
To calculate the concentration of base, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
Thus, the concentration of the NaOH solution is, 0.738 M
Answer:
The right response is "6 A". A further explanation is given below.
Explanation:
The given values are:
Resistance,
R = 6 ohms
Voltage,
V = 36 volts
As we know,
⇒
then,
⇒
On substituting the values, we get
⇒
⇒
Answer:- B. 4.65 g.
Solution:- The given balanced equation is:
It asks to calculate the mass of silver sulfide formed by when 0.0150 liters of 2.50 M of silver nitrate are used.
Moles of silver nitrate are calculated on multiplying it's liters by its molarity and then on multiplying by mol ratio, the moles of silver sulfide are calculated. These moles are multiplied by the molar mass to convert to the grams.
Molar mass of = 2(107.87)+32.06 = 247.8 g per mol
The dimensional set up for the complete problem is:
=
So, the correct choice is B. 4.65 g.