Answer:
17.3124 grams
Explanation:
Given;
Amount of heat to be produced = 175 kJ
Molar mass of the carbon monoxide = 12 + 16 = 28 grams
Now,
The standard molar enthalpy of carbon monoxide = 283 kJ/mol
Thus,
To produce 175 kJ heat, number of moles of CO required will be
= Amount heat to be produced / standard molar enthalpy of CO
or
= 175 / 283
= 0.6183
Also,
number of moles = Mass / Molar mass
therefore,
0.6183 = Mass / 28
or
Mass of the CO required = 0.6183 × 28 = 17.3124 grams
Answer: Temperature in constant pressure is 286 K
Explanation: If pressure remains constant, then V/T = constant.
V1 = 350 ml and T1 = 200 K and V2 = 500 ml. V1/T1 = V2/T2
and T2 = T1· V2 / V1 = 200 K · 500 ml / 300 ml = 285,7 K
<h2>
Answer:</h2>
- Cu(s) + 2AgNO3(aq) → Cu(NO3)2(aq) + 2Ag(s).
<u>Moles Cu present</u> = 100g Cu x 1 mol Cu/63.55g
= 1.574moles Cu
<u>Mass of Ag produced</u> = 1.574mol Cu x 2mol Ag / 1mol Cu x 107.9g Ag/mol Ag
= 340.g Ag
The mass is located in the necleus.
Answer:
2H+ + 2e - ---> H2(g) is the cathode
2Cl - ---> Cl2(g) + 2e - is the anode
Explanation:
Hydrogen ion has gained two electrons, making it undergo reduction. While chlorine has lose two electrons, hence undergoing oxidation.
