How many moles CH3OH are in 14.8 g CH3OH?

1 answer:

8 0

Answer:

15.17g.....................

Explanation:

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Zinaida [17]

The answer is C. 299k

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3 years ago

Evgesh-ka [11]

$V=277cm^{3}\\
m=928g\\\\
d=\frac{m}{V}=\frac{928g}{277cm^{3}}\approx3,35\frac{g}{cm^{3}}$

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Leto [7]

Neutrons which doesn't have any charge

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Xelga [282]

Density of liquid= $\frac{mass of liquid}{volume of liquid}$ .

so, density of liquid= $\frac{42 gm}{35 cm^{3} }$ = 1.2 gm/cm³.

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Lady_Fox [76]

the sugar disolved into the water so its a mixture. boom those words are it

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3 years ago

How many moles CH3OH are in 14.8 g CH3OH?​