All categories

3 years ago

What is the process of grouping similar things together

Chemistry

1 answer:

andre [41]3 years ago

8 0

Answer:

See Explanation

Explanation:

Mathematically, this means to combine like terms, such as terms with the same variable. In chemistry, this can refer to polar objects combining with polar objects while nonpolar objects combine with nonpolar objects.

You might be interested in

Newton's Law of Gravity says that any the effect of gravity between two objects depends on what two factors?

maw [93]

The masses of the objects and the distance between them
-hope it helps

8 0

2 years ago

What is true about energy in an ordinary chemical reaction? Energy is

Lisa [10]

The answer is statement #3.

4 0

3 years ago

Read 2 more answers

A silicon wafer with dimensions 15.00 cm x 15.00 cm x 0.0400 cm

Oxana [17]

The silicon wafer contains 20.96 g of silicon.

The mole of a substance is related to its mass and molar mass by the following equation:

<h3>Mole = mass / molar mass ....... (1)</h3>

Making mass the subject of the above equation, we have

<h3>Mass = mole × molar mass ..... (2)</h3>

With the above formula (i.e equation 2), we can obtain the mass of silicon in the wafer as follow:

Mole silicon = 0.746 mole

Molar mass of silicon = 28.09 g/mol

<h3>Mass of silicon =? </h3>

Mass = mole × molar mass

Mass = 0.746 × 28.09

<h3>Mass of silicon = 20.96 g</h3>

Therefore, the mass of silicon in the wafer is 20.96 g

Learn more: brainly.com/question/24639749

3 0

2 years ago

If 28 grams of N reacts completely with 12 grams of H2, then how many

Bogdan [553]

Answer:

Mass of NH₃ produced = 34 g

Explanation:

Given data:

Mass of nitrogen = 28 g

Mass of Hydrogen = 12 g

Mass of NH₃ produced = ?

Solution:

Chemical equation:

N₂ + 3H₂ → 2NH₃

Moles of nitrogen:

Number of moles = mass/molar mass

Number of moles = 28 g/ 28 g/mol

Number of moles = 1 mol

Moles of hydrogen:

Number of moles = mass/molar mass

Number of moles = 12 g/ 2 g/mol

Number of moles = 6 mol

Now we will compare the moles of hydrogen and nitrogen with ammonia.

H₂ : NH₃

3 : 2

6 : 2/3×6 = 4 mol

N₂ : NH₃

1 : 2

Number of moles of ammonia produced by nitrogen are less thus it will act as limiting reactant.

Mass of ammonia produced:

Mass = number of moles × molar mass

Mass = 2 mol × 17 g/mol

Mass = 34 g

5 0

3 years ago

Read 2 more answers

A sample of a compound is decomposed in the laboratory and produces 330 g carbon, 69.5 g hydrogen, and 220.2 g oxygen. Calculate

Zarrin [17]

Answer: Empirical formula is $C_2H_5O$

Explanation: We are given the masses of elements present in a sample of compound. To evaluate empirical formula, we will be following some steps.

<u>Step 1 :</u> Converting each of the given masses into their moles by dividing them by Molar masses.

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of Carbon = 12.0 g/mol

Molar mass of Hydrogen = 1.0 g/mol

Molar mass of Oxygen = 16.0 g/mol

Moles of Carbon = $\frac{330g}{12g/mol}=27.5moles$

Moles of Hydrogen = $\frac{69.5g}{1g/mol}=69.5moles$

Moles of Oxygen = $\frac{220.2g}{16g/mol}=13.76moles$

<u>Step 2: </u>Dividing each mole value by the smallest number of moles calculated above and rounding it off to the nearest whole number value

Smallest number of moles = 13.76 moles

$\text{Mole ratio of Carbon}=\frac{27.5moles}{13.76moles}=1.99\approx 2$

$\text{Mole ratio of Hydrogen}=\frac{69.5moles}{13.76moles}=5.05\approx 5$

$\text{Mole ratio of Oxygen}=\frac{13.76moles}{13.76moles}=1$

<u>Step 3:</u> Now, the moles ratio of the elements are represented by the subscripts in the empirical formula

Empirical formula becomes = $C_2H_5O$

7 0

3 years ago