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attashe74 [19]
3 years ago
13

A computer online service charges one hourly rate for regular use but a higher hourly rate for designated "premium" areas. One c

ustomer was charged $38 after spending 2 h in premium areas and 9 regular hours. Another customer spent 3 h in premium areas and 6 regular hours and was charged $34.50. What is the service charge per hour for regular and premium services?
Mathematics
1 answer:
N76 [4]3 years ago
8 0

Answer: the service charge per hour for premium services is $5.5

the service charge per hour for regular services is $3

Step-by-step explanation:

Let x represent the service charge per hour for premium services.

Let y represent the service charge per hour for regular services.

One customer was charged $38 after spending 2 h in premium areas and 9 regular hours. It means that

2x + 9y = 38- - - - - - - - - - - 1

Another customer spent 3 h in premium areas and 6 regular hours and was charged $34.50. It means that

3x + 6y = 34.5- - - - - - - - - - -2

We would eliminate x by multiplying equation 1 by 3 and equation 2 by 2. It becomes

6x + 27y = 114

6x + 12y = 69

Subtracting, it becomes

15y = 45

y = 45/15

y = 3

Substituting y = 3 into equation 1, it becomes

2x + 9 × 3 = 38

2x + 27 = 38

2x = 38 - 27 = 11

x = 11/2 = 5.5

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The ratio is 21.1 now give me my 33 dolar
3 0
3 years ago
What is the third term in the binomial expansion of (3x + y)4?
e-lub [12.9K]

Answer:

D on edge

Step-by-step explanation:

81 x^4+108x^3y^3+54x^2y^6+12xy^9+y^12 is the full extended form

So that means 54x^2y^6 is the answer

8 0
3 years ago
Read 2 more answers
Is this correct? if not what is the answer
LenaWriter [7]

Answer:

x = 50

Step-by-step explanation:

You are correct.

x + m<PQS + m<PSQ = 180

m<PQS = m<QRT = 70

m<QST + m<PSQ = 180

120 + m<PSQ = 180

m<PSQ = 60

x + 70 + 60 = 180

x + 130 = 180

x = 50

Great job!

4 0
3 years ago
The rate at which rain accumulates in a bucket is modeled by the function r given by r(t)=10t−t^2, where r(t) is measured in mil
mars1129 [50]

Answer:

36 milliliters of rain.

Step-by-step explanation:

The rate at which rain accumluated in a bucket is given by the function:

r(t)=10t-t^2

Where r(t) is measured in milliliters per minute.

We want to find the total accumulation of rain from <em>t</em> = 0 to <em>t</em> = 3.

We can use the Net Change Theorem. So, we will integrate function <em>r</em> from <em>t</em> = 0 to <em>t</em> = 3:

\displaystyle \int_0^3r(t)\, dt

Substitute:

=\displaystyle \int_0^3 10t-t^2\, dt

Integrate:

\displaystyle =5t^2-\frac{1}{3}t^3\Big|_0^3

Evaluate:

\displaystyle =(5(3)^2-\frac{1}{3}(3)^3)-(5(0)^2-\frac{1}{3}(0)^3)=36\text{ milliliters}

36 milliliters of rain accumulated in the bucket from time <em>t</em> = 0 to <em>t</em> = 3.

4 0
3 years ago
6.29 rounded to a whole number
Mandarinka [93]
If your were to round 6.29 to the nearest whole number it would round to 6, because the tenths place is less than 5.
7 0
3 years ago
Read 2 more answers
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