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attashe74 [19]
3 years ago
13

A computer online service charges one hourly rate for regular use but a higher hourly rate for designated "premium" areas. One c

ustomer was charged $38 after spending 2 h in premium areas and 9 regular hours. Another customer spent 3 h in premium areas and 6 regular hours and was charged $34.50. What is the service charge per hour for regular and premium services?
Mathematics
1 answer:
N76 [4]3 years ago
8 0

Answer: the service charge per hour for premium services is $5.5

the service charge per hour for regular services is $3

Step-by-step explanation:

Let x represent the service charge per hour for premium services.

Let y represent the service charge per hour for regular services.

One customer was charged $38 after spending 2 h in premium areas and 9 regular hours. It means that

2x + 9y = 38- - - - - - - - - - - 1

Another customer spent 3 h in premium areas and 6 regular hours and was charged $34.50. It means that

3x + 6y = 34.5- - - - - - - - - - -2

We would eliminate x by multiplying equation 1 by 3 and equation 2 by 2. It becomes

6x + 27y = 114

6x + 12y = 69

Subtracting, it becomes

15y = 45

y = 45/15

y = 3

Substituting y = 3 into equation 1, it becomes

2x + 9 × 3 = 38

2x + 27 = 38

2x = 38 - 27 = 11

x = 11/2 = 5.5

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Remark

You have to read this carefully to know what way to write it.

One way you could write it would be

20 * x = 18 where x is  the fraction. Now all you need do is divide.

Divide both sides by 20

20/20 * x = 18/20

\text{x = } \dfrac{18}{20}

But you should reduce this fraction. The way to do that is to factor 18 and 20 into primes.

18: 2 * 3 * 3

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Cancel out the Highest common factor or 2.

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\text{x = } \dfrac{18}{20} =\dfrac{2*3*3}{2*2*5}=\dfrac{3*3}{2*5} = \dfrac{9}{10} <<<< Answer

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Can someone solve this? Please!!!!<br> You just need to solve for X in the drawing
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Which of the following is a transformation of the graph y = (x - 5)^2?
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If θ is an angle in standard position that terminates in Quadrant III such that tanθ = 5/12, then sinθ/2 = _____
babunello [35]

Answer:

sin θ/2=5√26/26=0.196

Step-by-step explanation:

θ ∈(π,3π/2)

such that

θ/2 ∈(π/2,3π/4)

As a result,

0<sin θ/2<1, and

-1<cos θ/2<0

tan θ/2=sin  θ/2/cos θ/2

such that

tan θ/2<0

Let

t=tan θ/2

t<0

By the double angle identity for tangents

2 tan θ/2/1-(tanθ /2)^2  = tanθ

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Solve this quadratic equation for t :

t1=1/5 and

t2= -5

Discard t1 because t is not smaller than 0

Let s= sin θ/2

0<s<1.

By the definition of tangents.

tan θ/2= sin θ/2/ cos θ/2

Apply the Pythagorean Algorithm to express the cosine of θ/2 in terms of s. Note the cos θ/2 is expected to be smaller than zero.

cos θ/2 = -√1-(sin θ/2)^2 = - √1-s^2

Solve for s.

s/-√1-s^2 = -5

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s=√25/26 = 5√26/26

Therefore

sin θ/2=5√26/26=0.196....

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3 years ago
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