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Sergio039 [100]
4 years ago
8

Answers should be exact decimals (please do not leave as fractions or unfinished calculations).

Mathematics
1 answer:
aksik [14]4 years ago
8 0

Answer:

P(rolling the die results in a 3 or a 6)=0.3333

P(rolling the die results in not getting a 6)=0.8333

P(rolling the die results in the number being either greater than 2 or less than 5)=0.3333

P(rolling the die results in an even number or a 5)=0.6667

P( rolling the die twice results in a 6 followed by a 4)=0.0278

P(rolling the die three times results in all 6's)=0.0046

Step-by-step explanation:

a)

As the all outcomes are equally likely, so each number has equal probability of occurring.

For six sided die the sample space is {1,2,3,4,5,6} and each outcome has equal probability of 1/6.

1)

P(rolling the die results in a 3 or a 6)

P(rolling the die results in a 3 or a 6)=P(3)+P(6)=1/6+1/6=2/6=1/3

P(rolling the die results in a 3 or a 6)=0.3333

P(rolling the die results in not getting a 6)

P(rolling the die results in not getting a 6)=1-P(6)=1-1/6=5/6

P(rolling the die results in not getting a 6)=0.8333

P(rolling the die results in the number being either greater than 2 or less than 5)

number either greater than 2 or less than 5={3,4}

P(rolling the die results in the number being either greater than 2 or less than 5)=2/6=1/3

P(rolling the die results in the number being either greater than 2 or less than 5)=0.3333

P(rolling the die results in an even number or a 5)

number is an even number or a 5={2,4,5,6}

P(rolling the die results in an even number or a 5)=4/6=2/3

P(rolling the die results in an even number or a 5)=0.6667

P( rolling the die twice results in a 6 followed by a 4)

For six sided die rolled twice the sample space is

S={(1,1),(1,2),(1,3),(1,4),(1,5),(1,6),(2,1),(2,2),(2,3),(2,4),(2,5),(2,6),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}.

n(S)=6²=36.

rolling the die twice results in a 6 followed by a 4={(6,4)}

P( rolling the die twice results in a 6 followed by a 4)=1/36.

P( rolling the die twice results in a 6 followed by a 4)=0.0278

P(rolling the die three times results in all 6's)

When three die are rolled the number of outcomes=n(S)=6³=216.

rolling the die three times results in all 6's={(6,6,6)}

P(rolling the die three times results in all 6's)=1/216

P(rolling the die three times results in all 6's)=0.0046

Note: All answers are rounded to four decimal places.

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"if the standard deviation of a group of 20 scores is 15, what is the variance?"
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We have been given that the standard deviation of a group of 20 scores is 15 and we are asked to find variance.

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How do you multiply 3 different numbers?
sasho [114]
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4 years ago
Jenny opened a package of screws quickly and many of them spilled on the floor. She needs to organize the fasteners according to
hichkok12 [17]

We have to compare diameters and arrange them in order smallest to greatest

We can see units for option A and B are in square inches so they represents area. So first we will find diameter from area using formula

A = \pi r^{2}

so for choice (A) area is given as 4.375 \times 10^{7}. So plug this in A place in formula and then solve for radius r

4.375 \times 10^{7} = \pi r^{2}

\frac{4.375 \times 10^{7}}{\pi}   = \frac{\pi r^{2}}{\pi}

1.393 \times 10^{7} } =  r^{2}

\sqrt{1.393 \times 10^{7}}  = \sqrt{r^{2}}

3731.76 = r

So screw A will have
diameter = 2 \times r = 2 \times 3731.76 = 7463.52 inches

Similarly for choice (E) area is 1.428 \times 10^{1} = 14.28
so again plug in formula

A = \pi r^{2}

14.28 = \pi r^{2}

\frac{14.28}{\pi}   = \frac{\pi r^{2}}{\pi}

4.5477 =  r^{2}

\sqrt{4.5477}  = \sqrt{r^{2}}

2.13201 = r

So screw E will have
diameter = 2 \times r = 2 \times 2.13201 = 4.26402 inches

So diameters of all screws are as follows:

Screw A: 7463.52 inches
Screw B: 1.5 inches
Screw C: 1\frac{7}{8} =  \frac{1\times 8+7}{8} = \frac{15}{8} = 1.875 inches
Screw D: 0.25 inches
Screw E: 4.26402 inches

Comparing all numbers 7463.52, 1.5, 1.875, 0.25, 4.26402 we can see that smallest number is 0.25, then comes 1.5, then 1.875 and then 4.26402 and then 7463.52

So order from least to greatest will be screw D (0.25), B(1.5), C(1.875), E (4.26402), A (7463.52).

So thats the order D,B,C,E,A and the final answer

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I need help on this question
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if an arc measures 179 it would be a

Minor arc

6 0
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