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mash [69]
2 years ago
10

Which graph shows the solution set

Mathematics
1 answer:
Anna007 [38]2 years ago
5 0

Answer:

D

Step-by-step explanation:

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Pls help me someone
Lynna [10]
Y=-1/3x+4

x2-x1/ y2-y1
(0,4)(2,-2)
2-0/-2-4
1/-3

y-intercept is 4

y=-1/3x+4
3 0
2 years ago
Elaine opens a checking account with a deposit of $20.00 and wants to put the same amount of money
Snowcat [4.5K]

Answer: 200 = m x 10 + 20

Step-by-step explanation:

She wants a balance of 200 with the same amount of money (m) going into the account for 10 weeks plus the amount she began with

7 0
3 years ago
The vertex of -5(x+2)^2-6
4vir4ik [10]

Answer:

(0,6).  

Step-by-step explanation:

Consider the standardised form of y=ax2+bx+c. Written as y=a(x2+bax)+c. xvertex=(−12)×ba → (−12)×0−1=0.

Mark me brainliest

7 0
2 years ago
Lupe’s Construction is building a rectangular house that is 16 feet longer than it is wide. They will be putting a 3-foot wide s
mr Goodwill [35]

Answer:

The length of the four pieces of protective strip is 96 feet

Step-by-step explanation:

Let the w be the width of the rectangular house and L is length. Since L = w + 16, its perimeter P = 2(w + L)

= 2(w + w + 16)

= 2(2w + 16)

Since the perimeter of the house P = 136 feet,

136 = 2(2w + 16)

dividing through by 2, we have

136/2 = (2w + 16)

68 = (2w + 16)

collecting like terms, we have

68 - 16 = 2w

52 = 2w

dividing through by 2, we have

w = 52/2

w = 26 feet.

Now, since the side walk is 3 foot wide all around, the width of the house plus sidewalk = w + 3 and the length of the house plus sidewalk = L + 3 = w + 16 + 3 = w + 19.

So, the perimeter of the house plus sidewalk which is the perimeter of the four pieces of protective strip is P' = 2(w + 3 + w + 19)

= 2(w + 22)

= 2(26 + 22)

= 2(48)

= 96 feet

So, the length of the four pieces of protective strip is 96 feet.

5 0
3 years ago
If log 5 = p and log 2=q then log 200 can be written in terms of p and q as?
Andrei [34K]
<h3>Answer:  2p + 3q</h3>

Work Shown:

log(200) = log(2^3*5^2)

log(200) = log(2^3) + log(5^2)

log(200) = 3*log(2) + 2*log(5)

log(200) = 3*q + 2*p

log(200) = 2p + 3q

The log rules I used were

log(A*B) = log(A)+log(B)

log(A^B) = B*log(A)

8 0
2 years ago
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