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mihalych1998 [28]
2 years ago
13

A man bought a refrigerator, an air conditioner, a TV set and a gas cooker for $150.00, $400.00, $180.00 and $300.00 respectivel

y. In addition he pays 15% VAT for each item. Calculate
Total VAT collected from him
Total amount he had to pay.
Mathematics
1 answer:
MaRussiya [10]2 years ago
4 0

Answer:

1184.5

Step-by-step explanation:

150+400+180+300=1030

1030 × 15% = 154.5

(15% is also 0.15)

1030 + 154.5 = 1184.5

I hope this helps you :)

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I need help with this, it's due in 15 mins-
LiRa [457]

Answer:

Mean: 3.5263157894737

Median: 3

Mode: 3

Step-by-step explanation: The mode is 3 because the mode is for which number pops up the most, which is 3.

I got the median by crossing out 8 from the left and the right of the number set and got 3 as the last number.

I got the mean by adding up all the numbers and divided it by the amount of numbers in the set.

3 0
3 years ago
GEOMETRY. PLEASE HELP. I'M STUMPED!!!
tatiyna
Given the triangles ABC and PQR.
Angle A = Angle P
Angle B = Angle Q
Angle C = Angle R

Angle B = 3v+4
Angle Q = 8v-6
Let's find v

3v+4 = 8v-6
-5v = -10
v = 2

Angle B = 3v + 4
Angle B = 3(2) + 4
Angle B = 10.

The correct answer is letter C. 10


8 0
3 years ago
Ashley posts 17 status updates on her Facebook wall each day . Roberto posts 21 status updates on his Facebook wall each day .
shutvik [7]

Let x be the number of days.  

If Ashley posts 17 status updates each day, then after x days Ashley posts 17x status updates.

If Roberto posts 21 status updates each day, then after x days Roberto posts 21x status updates.

Part A. The combined number of posts for Ashley and Roberto after x days is:

17x+21x.

Part B. The difference between number of posts for Ashley and Roberto after x days is:

21x-17x.

4 0
3 years ago
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Please help and tell me how to do this <br> 20 POINTS
svp [43]
The answers are :
13) 9
14) 200
15) -10
16) -300

17) -276
18) -66
3 0
2 years ago
Read 2 more answers
PRECAL:<br> Having trouble on this review, need some help.
ra1l [238]

1. As you can tell from the function definition and plot, there's a discontinuity at x = -2. But in the limit from either side of x = -2, f(x) is approaching the value at the empty circle:

\displaystyle \lim_{x\to-2}f(x) = \lim_{x\to-2}(x-2) = -2-2 = \boxed{-4}

Basically, since x is approaching -2, we are talking about values of x such x ≠ 2. Then we can compute the limit by taking the expression from the definition of f(x) using that x ≠ 2.

2. f(x) is continuous at x = -1, so the limit can be computed directly again:

\displaystyle \lim_{x\to-1} f(x) = \lim_{x\to-1}(x-2) = -1-2=\boxed{-3}

3. Using the same reasoning as in (1), the limit would be the value of f(x) at the empty circle in the graph. So

\displaystyle \lim_{x\to-2}f(x) = \boxed{-1}

4. Your answer is correct; the limit doesn't exist because there is a jump discontinuity. f(x) approaches two different values depending on which direction x is approaching 2.

5. It's a bit difficult to see, but it looks like x is approaching 2 from above/from the right, in which case

\displaystyle \lim_{x\to2^+}f(x) = \boxed{0}

When x approaches 2 from above, we assume x > 2. And according to the plot, we have f(x) = 0 whenever x > 2.

6. It should be rather clear from the plot that

\displaystyle \lim_{x\to0}f(x) = \lim_{x\to0}(\sin(x)+3) = \sin(0) + 3 = \boxed{3}

because sin(x) + 3 is continuous at x = 0. On the other hand, the limit at infinity doesn't exist because sin(x) oscillates between -1 and 1 forever, never landing on a single finite value.

For 7-8, divide through each term by the largest power of x in the expression:

7. Divide through by x². Every remaining rational term will converge to 0.

\displaystyle \lim_{x\to\infty}\frac{x^2+x-12}{2x^2-5x-3} = \lim_{x\to\infty}\frac{1+\frac1x-\frac{12}{x^2}}{2-\frac5x-\frac3{x^2}}=\boxed{\frac12}

8. Divide through by x² again:

\displaystyle \lim_{x\to-\infty}\frac{x+3}{x^2+x-12} = \lim_{x\to-\infty}\frac{\frac1x+\frac3{x^2}}{1+\frac1x-\frac{12}{x^2}} = \frac01 = \boxed{0}

9. Factorize the numerator and denominator. Then bearing in mind that "x is approaching 6" means x ≠ 6, we can cancel a factor of x - 6:

\displaystyle \lim_{x\to6}\frac{2x^2-12x}{x^2-4x-12}=\lim_{x\to6}\frac{2x(x-6)}{(x+2)(x-6)} = \lim_{x\to6}\frac{2x}{x+2} = \frac{2\times6}{6+2}=\boxed{\frac32}

10. Factorize the numerator and simplify:

\dfrac{-2x^2+2}{x+1} = -2 \times \dfrac{x^2-1}{x+1} = -2 \times \dfrac{(x+1)(x-1)}{x+1} = -2(x-1) = -2x+2

where the last equality holds because x is approaching +∞, so we can assume x ≠ -1. Then the limit is

\displaystyle \lim_{x\to\infty} \frac{-2x^2+2}{x+1} = \lim_{x\to\infty} (-2x+2) = \boxed{-\infty}

6 0
2 years ago
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