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Wewaii [24]
3 years ago
14

6.An acid-base indicator is usually a weak acid with a characteristic color in the protonated and deprotonated forms. Because br

omocresol green is an acid, it is convenient to represent its rather complex formula as HBCG. HBCG ionizes in water according to the following equation:HBCG + H2O = BCG- + H3O+ (yellow)(blue)The Ka (the equilibrium constant for the acid) expression is: Ka=[BCG−][H3O+][HBCG]When [BCG-] = [HBCG], then Ka = [H3O+]. If you know the pH of the solution, then the [H3O+] and Ka can be determined. What would be the color of the solution if there were equal concentrations of HBCG and BCG-?Solution Color: _______________What is the pH at the first appearance of this color?Solution pH: __________What is an estimate for the Ka for bromocresol green? Show your work to get full credit
Chemistry
1 answer:
Eddi Din [679]3 years ago
5 0

Answer:

At equal concentration of HBCG and BCG^-, the colour is green. This colour first appears at pH = 3.8

Explanation:

HBCG is an indicator that is prepared by dissolving the solid in ethanol.

Since

Ka=[BCG−][H3O+][HBCG]When [BCG-] = [HBCG], then Ka = [H3O+].

If pH = 3.8

Ka= [H3O+] = -antilog pH = -antilog (3.8)

Ka= 1.58 ×10^-4

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hope this helps 
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5 0
3 years ago
An object has a density of 16.3 g/mL and a volume of 0.46 L. Calculate the
deff fn [24]

Answer:

16.53 pounds

Explanation:

this type of problem needs convertion method we need to convert from grams to pound.

3 0
3 years ago
Is this statement true or false? Ammonia is a base. A. True B. False
Sever21 [200]
It is true.
Hope it helps :)


6 0
4 years ago
Read 2 more answers
A saline solution contains 72.3 grams of NaCl in 500.0 mL if water. What is the concentration (Molarity) of this solution?
valina [46]

Answer:

2.47 M

Explanation:

Molarity is (mol of solute)/(L of solvent).  To find molarity, convert grams of NaCl to moles of NaCl and milliliters of water to liters of water.

72.3 g ÷ 58.44 g/mol = 1.2372... mol

500 mL ÷ 1000 mL = 0.5 L

Molarity = 1.2372/0.5 = 2.47 M

7 0
3 years ago
How many moles of solve (Ag) are equivalent to 68.3g Ag
Zina [86]
Moles Ag = 68.3 g / 107.868 g/mol=0.633
5 0
4 years ago
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