The number of liters of 3.00 M lead (II) iodide : 0.277 L
<h3>Further explanation</h3>
Reaction(balanced)
Pb(NO₃)₂(aq) + 2KI(aq) → 2KNO₃(aq) + PbI₂(s)
moles of KI = 1.66
From the equation, mol ratio of KI : PbI₂ = 2 : 1, so mol PbI₂ :
Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution
Where
M = Molarity
n = Number of moles of solute
V = Volume of solution
So the number of liters(V) of 3.00 M lead (II) iodide-PbI₂ (n=0.83, M=3):
Answer:
It’s is a simple
Explanation:the prokaryotic cell involves a simple process which intern involves one chromosom
Explanation:
Because There are 6.022x10^23 atoms per mole; therefore, (6.022x10^23×3)=18.066x10^23 atoms of titanium.
Solution :
Molecular mass of NaOH is 23 g/mol .
So, number of moles of NaOH is given by :
Now, we know molarity is given by :
Hence, this is the required solution.
When a liquid releases enough energy<span>. the </span>liquid<span> freezes, changing to a solid.
Hope this answer helps! feel free to ask any additional questions :)</span>
