Answer:
36.8 L
Explanation:
We'll begin by converting 80 °C to Kelvin temperature. This can be obtained as follow:
T(K) = T(°C) + 273
T(°C) = 80 °C
T(K) = 80 + 273
T(K) = 353 K
Finally, we shall determine the volume occupied by the helium gas. This can be obtained as follow:
Number of mole (n) = 1.27 moles
Temperature (T) = 353 K
Pressure (P) = 1 atm
Gas constant (R) = 0.0821 atm.L/Kmol
Volume (V) =?
PV = nRT
1 × V = 1.27 × 0.0821 × 353
V = 36.8 L
Thus, the volume occupied by the helium gas is 36.8 L
Quantitative data is numerical.
Qualitative data is non-numerical.
Hope this helps.
have a great day.
Answer:
answer A because it's not sustainable and it is overfishing a population
The number of mole of nitrogen that occupies 1.2 L under the same condition is 0.6 mole
<h3>Data obtained from the question </h3>
- Initial mole (n₁) = 0.2 mole
- Initial volume (V₁) = 0.4 L
- Final volume (V₂) = 1.2 L
- Final mole (n₂) =?
<h3>How to determine the final mole </h3>
The final mole can be obtained by using the ideal gas equation as illustrated below:
PV = nRT
Divide both side n
PV / n = RT
Divide both side by P
V / n = RT / P
RT / P = constant
V / n = constant
Thus,
V₁ / n₁ = V₂ / n₂
0.4 / 0.2 = 1.2 / n₂
2 = 1.2 / n₂
Cross multiply
2 × n₂ = 1.2
Divide both side by 2
n₂ = 1.2 / 2
n₂ = 0.6 mole
Learn more about ideal gas equation:
brainly.com/question/4147359
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