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jenyasd209 [6]
3 years ago
15

True or False?

Chemistry
2 answers:
Iteru [2.4K]3 years ago
4 0
This is true, " To increase acceleration of an object, you reduce its MASS or increase the applied force."
kvv77 [185]3 years ago
3 0
It is true hope it helps
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In a DNA sample, 15% of the bases are thymine (T). What percentage of the bases in this sample are cytosine (C)?
allochka39001 [22]

Answer:

C) 35%

Explanation:

Thymine pairs with adenine. If thymine is 15% then so would adenine be 15%. That leaves the reaminder to be 70%. Cytosine pairs with guanine, thereby, they would each be 35%.

3 0
3 years ago
Fill in the blank with the correct response.
Ganezh [65]

Surveys are the data collection tool and research methods. The questionnaire survey tool is used to collect the data based on questions.

<h3>What are questionnaires?</h3>

Questionnaires are the tool used for the research and the data collection for the analysis, investigation, and conclusion. It is one of the data collection tools that comprises questions and prompts.

Questionnaires are the part of surveys that gathers information on the topic of the research and is easy to analyze and cost-effective. It is a valuable tool that collects data from a large number of participants.

Therefore, the correct blank is the <u>questionnaire</u>.

Learn more about the questionnaire here:

brainly.com/question/20335282

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3 0
1 year ago
During the chemical reaction given below 21.71 grams of each reagent were allowed to react. Determine how many grams of the exce
swat32

Answer: 16.32 g of O_2 as excess reagent are left.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} SO_2=\frac{21.71g}{64g/mol}=0.34mol

\text{Moles of} O_2=\frac{21.71g}{32g/mol}=0.68mol

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)  

According to stoichiometry :

2 moles of SO_2 require = 1 mole of O_2

Thus 0.34 moles of SO_2 will require=\frac{1}{2}\times 0.34=0.17moles  of O_2

Thus SO_2 is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

Moles of O_2 left = (0.68-0.17) mol = 0.51 mol

Mass of O_2=moles\times {\text {Molar mass}}=0.51moles\times 32g/mol=16.32g

Thus 16.32 g of O_2 as excess reagent are left.

3 0
2 years ago
45.7 grams of calcium chloride reacts with an excess of aluminum oxide. How many grams of aluminum chloride will be produced
damaskus [11]
Molar mass (CaCl2) = 40.1 +2*35.5 = 111.1 g/mol
Molar mass (AlCl3) = 27.0 +3*35.5= 133.5 g/ mol

                                               
3CaCl2+Al2O3 -------->3CaO +2AlCl3
mole from reaction              3 mol                                              2 mol
mass from reaction         3mol* 111.1g/mol                             2 mol*133.5g/mol
                                               333.3 g                                            267.0 g
mass from problem              45.7 g                                               x g

Proportion:
  333.3 g  CaCl2  -------   267.0 g AlCl3
  45.7 g   CaCl2   --------   x g    AlCl3

x=45.7*267.0/333.3= 36.6 g AlCl3
5 0
3 years ago
Usually, it is observed that climates in coastal regions are moderate as compared to climates in the interiors of continents. Wh
Stella [2.4K]
<span>Answer: option D) Conditions over the oceans change slowly because water takes more time than land to gain or lose heat.

This is because water has a high heat capacity meaning that, with the same amount of heat, it will change its temperature less than what substances with lower heat capacities do.
</span>
7 0
3 years ago
Read 2 more answers
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