Answer:
The answer is "4,241 .17 years"
Explanation:
The disintegration rate, which shows in C-14 atoms =
Rate of sample disintegration =
The digit proportion of C-14 can be determined that is included in the sample
5730 years from half-life.
The number with half-lives (n) which are repelled must be determined:
So, the age of the sample is given by =
Explanation:
1) Initial mass of the Cesium-137== 180 mg
Mass of Cesium after time t = N
Formula used :
Half life of the cesium-137 = = initial mass of isotope
N = mass of the parent isotope left after the time, (t)
= half life of the isotope
= rate constant
Now put all the given values in this formula, we get
Mass that remains after t years.
Therefore, the parent isotope remain after one half life will be, 100 grams.
2)
t = 70 years
N = 35.73 mg
35.73 mg of cesium-137 will remain after 70 years.
3)
N = 1 mg
t = ?
t = 224.80 years ≈ 225 years
After 225 years only 1 mg of cesium-137 will remain.
hydrogen and carbon, hope that helped