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tamaranim1 [39]
3 years ago
12

Solve this system of equations using any method.

Mathematics
1 answer:
Studentka2010 [4]3 years ago
5 0
If you use the elimination method, add both equations together to eliminate a variable. You will get 5x=15. x=3. Replace x in the equations with 3 to get y =7, so your answer is A, (3,7.) I hope his helped!. Please give brainliest!
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100 POINTS!<br> STATS<br> EXPLANATION NEEDED
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Answer:

Step-by-step explanation:

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If you flip a coin and roll a 6-sided die, what is the probability that you will flip a heads and roll a 1
Novosadov [1.4K]
P(H)=1/2, P(1)=1/6

P(H and 1)=(1/2)(1/6)=1/12  (≈8.33%)
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First and second place in a contest use a ratio to share a cash prize. When first place pays $100 , second place pays $60. How m
torisob [31]

Answer:

$60

Step-by-step explanation:

the ratio is 100:60 or 5/3

if second place pays 36, to find out how much first place pays, multiply 36 by 5/3

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3 years ago
An environmentalist wants to find out the fraction of oil tankers that have spills each month. Step 2 of 2 : Suppose a sample of
rewona [7]

Answer:

The 80% confidence interval for the population proportion of oil tankers that have spills each month is (0.199, 0.257).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

Suppose a sample of 333 tankers is drawn. Of these ships, 257 did not have spills.

333 - 257 = 76 have spills.

This means that n = 333, \pi = \frac{76}{333} = 0.228

80% confidence level

So \alpha = 0.2, z is the value of Z that has a pvalue of 1 - \frac{0.2}{2} = 0.9, so Z = 1.28.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.228 - 1.28\sqrt{\frac{0.228*0.772}{333}} = 0.199

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.228 + 1.28\sqrt{\frac{0.228*0.772}{333}} = 0.257

The 80% confidence interval for the population proportion of oil tankers that have spills each month is (0.199, 0.257).

6 0
3 years ago
Please help with steps:<br><br> 18 - 24 (divide) (-6)
bekas [8.4K]

Answer:

Solution is 1 (one).

Step-by-step explanation:

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4 0
3 years ago
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