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BartSMP [9]
3 years ago
10

A square has an area of 112 cm squared what is the approximate perimeter of the square

Mathematics
1 answer:
Andreas93 [3]3 years ago
4 0

Answer:

approximate perimeter is 42.32

Step-by-step explanation:

each side of a square is equal to each other

1. Find the square root of 112

10.58^2 = 112

2. Multiply 10.58 by 4(number of sides)

10.58(4) = 42.32

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Step-by-step explanation:

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They have the same slope. All three lines are parallel. Any parallel lines have equal slopes.
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21r-7-r+5=-52 solve for r
malfutka [58]

Answer:

r = - 2.5

r=-2\frac{1}{2}

Step-by-step explanation:

21r - 7 - r + 5 = - 52

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An art history professor assigns letter grades on a test according to the following scheme. A: Top 13% of scores B: Scores below
madam [21]

Answer:

The numerical limits for a B grade are 81 and 89, that is, a score between 81 and 89 gets a B grade.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Scores on the test are normally distributed with a mean of 79.7 and a standard deviation of 8.4.

This means that \mu = 79.7, \sigma = 8.4

B: Scores below the top 13% and above the bottom 56%

So between the 56th percentile and the 100 - 13 = 87th percentile.

56th percentile:

X when Z has a p-value of 0.56, so X when Z = 0.15. Then

Z = \frac{X - \mu}{\sigma}

0.15 = \frac{X - 79.7}{8.4}

X - 79.7 = 0.15*8.4

X = 81

87th percentile:

X when Z has a p-value of 0.87, so X when Z = 1.13.

Z = \frac{X - \mu}{\sigma}

1.13 = \frac{X - 79.7}{8.4}

X - 79.7 = 1.13*8.4

X = 89

The numerical limits for a B grade are 81 and 89, that is, a score between 81 and 89 gets a B grade.

4 0
3 years ago
PLEASE HELP <br> suppose
charle [14.2K]

Answer:

steps below

Step-by-step explanation:

3 = 2/3 m

m = 9/2

by the matrix property of associative: (A+B)+C = A+(B+C)

H = [-2  8  -1]

m x H = 9/2 x [-2  8  1] = [-9  36  -9/2]

4 0
3 years ago
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