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Lynna [10]
3 years ago
5

If you flip a coin and roll a 6-sided die, what is the probability that you will flip a heads and roll a 1

Mathematics
2 answers:
ipn [44]3 years ago
7 0

Answer:

1/12

Step-by-step explanation:

Flipping a heads and rolling a 1 are independent event, they don't affect each other. So, to get the probability of both happening, we just need to multiply the probability of one y the probability of each other.

The probability of flipping a heads is 1/2.

The probability of rolling a 1 is 1/6, since there is 1 outcome which satisfies our condition (namely, 1), and 6 total possible outcomes.

So, the probability of both these events happening is 1/2*1/6=1/12

Hope this helps :) !

Novosadov [1.4K]3 years ago
4 0
P(H)=1/2, P(1)=1/6

P(H and 1)=(1/2)(1/6)=1/12  (≈8.33%)
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0 divided by 0 is? 45 points for who answer its correct not for a homework
Elenna [48]

Answer:

Undefined

Step-by-step explanation:

No multiplicative inverse exists for 0

4 0
1 year ago
Read 2 more answers
In triangle , side and the perpendicular bisector of meet in point , and bisects . If and , what is the area of triangle
stich3 [128]

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, 145–√5  is the area of a triangle.

I supposed here that [ABD] is the perimeter of ▲ ABD.

As  BD  is a bisector of  ∠ABC ,

ABBC=ADDC=97

Let  ∠B=2α

Then in isosceles  △DBC

∠C=α

BC=2∗DC∗cosα=14cosα

Thus  AB=18cosα

The Sum of angles in  △ABC  is  π  so

∠A=π−3α

Let's look at  AC=AD+DC=16 :

AC=BCcosC+ABcosA

16=14cos2α+18cosαcos(π−3α)

[1]8=7cos2α−9cosαcos(3α)

cos(3α)=cos(α+2α)=cosαcos(2α)−sinαsin(2α)=cosα(2cos2α−1)−2cosαsin2α=cosα(4cos2α−3)

With  [1]

8=cos2α(7−9(4cos2α−3))

18cos4−17cos2α+4=0

cos2α={12,49}

First root lead to  α=π4  and  ∠BDC=π−∠DBC−∠C=π−2α=π2 . In such case  ∠A=π−∠ABD−∠ADB=π4, and  △ABD  is isosceles with  AD=BD. As  △DBC  is also isosceles with  BD=DC=7,  AD=7≠9.

Thus first root  cos2α=12  cannot be chosen and we have to stick with the second root  cos2α=49. This gives  cosα=23  and  sinα=5√3.

The area of a triangle ABD=12h∗AD  where h  is the distance from  B  to  AC.

h=BCsinC=14cosαsinα

Area of  triangle ABD=145–√5

= 145–√5.

Incomplete question please read below for the proper question.

In triangle ABC, side AC and the perpendicular bisector of BC meet in point D, and BD bisects ∠ABC。 If AD = 9 and DC = 7, what is the area of triangle ABD?

Learn more about the Area of the triangle at

brainly.com/question/23945265

#SPJ4

6 0
2 years ago
A bus company changes a fixed amount plus a fee based on the distance traveled what is the fixed amount x =0,1,2 and y is 4,9,14
Rus_ich [418]

Answer:

$4

Step-by-step explanation:

Because with no distance traveled, the fixed amount charged would be $4. For every mile traveled, there is an additional $5. So your correct answer is $4.

8 0
3 years ago
24+3x=3x+3(7-1) What does x equal? Please show me how to do it I don't want the answer. (Well I do but show me how to get it als
balandron [24]

<span>                                               <u>24 + 3x = 3x + 3(7 - 1)</u>

Eliminate the parentheses:    24 + 3x = 3x + 3(6)

                                              24 + 3x = 3x + 18

Subtract  3x  from each side:       <em>24  =  18</em>

Look at that for a second.  Can ANY value of 'x' make 24 equal to 18 ?
I don't think so.
There's NO number that makes the equation a true statement.

That's just another way to say: "The equation has NO solution."</span>


5 0
3 years ago
The sum of the volume of two rectangular prisms, box a and box b are 14.325cm cubed. Box a has a volume of 5.61cm.
Galina-37 [17]

The equation that could be used to determine the volume of Box B is (B = 14.325cm³ - 5.61cm³) and the volume of Box B is 8.715cm³.

This question is incomplete, the complete question is:

The sum of the volume of two rectangular prisms, box a and box b are 14.325cm cubed. Box a has a volume of 5.61cm.

a. Let B represent the volume of Box B in cubic centimeters. Write an equation that could be used to determine the volume of Box B.

b. Solve the equation to determine the volume of Box B

<h3>What is volume?</h3>

Volume is simply the amount of space that is enclosed within a container.

Given that;

  • Sum of the volume of two rectangular prisms A&B = 14.325cm³
  • Volume of Box A = 5.61cm³

a)

Let B represent the volume of Box B in cubic centimeters. The equation that could be used to determine the volume of Box B will be;

Sum of the volume of two rectangular prisms A&B = Volume of Box A + Volume of Box B

14.325cm³ = 5.61cm³ + B

B = 14.325cm³ - 5.61cm³

Hence, The equation that could be used to determine the volume of Box B is B = 14.325cm³ - 5.61cm³

b)

To determine the volume of Box B, we solve the equation.

B = 14.325cm³ - 5.61cm³

B = 8.715cm³

Hence, the volume of Box B is 8.715cm³.

Learn more about volume rectangular prism here: brainly.com/question/9796090

#SPJ1

6 0
1 year ago
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