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Nutka1998 [239]
3 years ago
5

X2 + y2 + 6x – 2y+3 = 0? What is the radius of a circle with the equation

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
5 0

Answer:

Step-by-step explanation:

hello : write this expression

X² + y² + 6x – 2y+3 = 0  in the standard form

(x²+6x) +(y²-2y) +3 = 0

(x²+6x+9 -9) +(y²-2y+1 - 1) +3 = 0

(x²+6x+9) -9 +(y²-2y+1) - 1 +3 = 0

(x+3)²+(y-1)² = 7(the standard form)

but : 7 = (√7)²

<h2>the radius is : √7</h2>

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What is the equation of the line that passes through the point (-1, -7) and has a<br> slope of 2?
slava [35]

Answer:

y=2x-5

Step-by-step explanation:

The slope-intercept form of an equation looks like y=mx+b. Where m is the slope and b is the y-intercept. The slope is already given to us, so m is 2.

To find b use the equation b=y_1-m*x_1. So, to find the y-intercept use b=-7-(2*-1). This equals b=-5.

So, plug in the values to get the final equation y=2x-5.

7 0
2 years ago
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Find all values of m so that the function y= e^mx is a solution of the given differential equation.
son4ous [18]

Answer:

m = - 2 is the value of m that the function y= e^mx is a solution of the differential equation, y' + 2y = 0.

Step-by-step explanation:

To determine all values of m so that the function y= e^mx is a solution of the given differential equation.

First, we will find y'.

From, y= e^mx

y = e^{mx}

But, y' = \frac{d}{dx}y

Hence,

y' = \frac{d}{dx}e^{mx}\\

∴ y' = me^{mx}

Now, we will put the values of y' and y into the given differential equation y' + 2y =0

From the question,

y = e^{mx}

and

y' = me^{mx}

Then, y' + 2y =0\\ becomes

me^{mx} + 2(e^{mx}) = 0

Then, me^{mx} = - 2(e^{mx}) \\\\

m = \frac{-2(e^{mx}) }{e^{mx} } \\

∴ m = -2

Hence, m = - 2 is the value of m that the function y= e^mx is a solution of the differential equation, y' + 2y = 0.

3 0
3 years ago
-l-7+3l evaluate negative absolute value of negative 7 plus 3
kicyunya [14]
-l-7+3l =  -|-4| = -4

Answer: 
-4
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3 years ago
PLS HELP!!!!! What are the zeros of polynomial function <img src="https://tex.z-dn.net/?f=F%28x%29%20%3D%20x%5E4%20-%2010x%5E2%2
mina [271]

Answer:

heres the answer, in the screenshot.

6 0
2 years ago
Part 2 of 3
dlinn [17]

Considering that point S splits segment RT, we have that:

a) The value of y is of y = 4.

b) The lengths are: RS = 29, ST = 19.

<h3>How to find the value of variable y?</h3>

Point S splits segment RT into two parts, hence the length of segment RT can be given by the following equation:

RT = RS + ST

The measures are given as follows:

  • RS = 6y + 5.
  • ST = 3y + 7.
  • RT = 48.

Hence we can solve the equation for y, as follows:

RT = RS + ST

6y + 5 + 3y + 7 = 48.

9y = 36.

y = 4.

<h3>What are the lengths of segments RS and ST?</h3>

Considering that y = 4, we have that:

  • RS = 6y + 5 = 6(4) + 5 = 29.
  • ST = 3y + 7 = 3(4) + 7 = 19.

A similar problem, in which a point splits a segment, is given at brainly.com/question/4450896

#SPJ1

3 0
1 year ago
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