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madam [21]
4 years ago
6

If you purchase a software suite for personal use, you can install the software how many times on how many different machines?

Computers and Technology
1 answer:
givi [52]4 years ago
8 0

A software for personal use can be installed for a finite number of times as stated in the agreement signed between the customer and the supplier. Therefore the answer to this question is <span>“It depends upon the conditions stated in the license agreement”.</span>

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Write a client program ClientSorting2 and in the main() method: 1. Write a modified version of the selection sort algorithm (Sel
TEA [102]

Answer:

The program in Java is as follows:

import java.util.*;

public class Main{

 public static void SelectionSorter(String[] my_array){

     System.out.print("\nAfter sort: ");

     for (int ind=0; ind < 22; ind++ ){

         int min = ind;

         for (int k=ind+1; k < 23; k++ )

         if (my_array[k].compareTo(my_array[min] ) < 0 ){ min = k;  }

         String temp = my_array[ind];

         my_array[ind] = my_array[min];

         my_array[min] = temp;    }

   for (int j=0; j < 23; j++){   System.out.print(my_array[j]+" ");}

    }

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 String [] myarray = new String [23];

 for(int i= 0;i<23;i++){ myarray[i] = input.nextLine();  }

 System.out.print("Before sort: ");

 for ( int j=0; j < 23; j++ ){        System.out.print(myarray[j]+" ");    }

 SelectionSorter(myarray);

}

}

Explanation:

This defines the function

 public static void SelectionSorter(String[] my_array){

This prints the header for After sort

     System.out.print("\nAfter sort: ");

This iterates through the array

     for (int ind=0; ind < 22; ind++ ){

This initializes the minimum index to the current index

         int min = ind;

This iterates from current index to the last index of the array

         for (int k=ind+1; k < 23; k++ )

This compares the current array element with another

         if (my_array[k].compareTo(my_array[min] ) < 0 ){ min = k;  }

If the next array element is smaller than the current, the elements are swapped

<em>          String temp = my_array[ind];</em>

<em>          my_array[ind] = my_array[min];</em>

<em>          my_array[min] = temp;    }</em>

This iterates through the sorted array and print each array element

   for (int j=0; j < 23; j++){   System.out.print(my_array[j]+" ");}

    }

The main begins here

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

This declares the array

 String [] myarray = new String [23];

This gets input for the array elements

 for(int i= 0;i<23;i++){ myarray[i] = input.nextLine();  }

This prints the header Before sort

 System.out.print("Before sort: ");

This iterates through the array elements and print them unsorted

 for ( int j=0; j < 23; j++ ){        System.out.print(myarray[j]+" ");    }

This calls the function to sort the array

 SelectionSorter(myarray);

}

}

3 0
3 years ago
Which of the following is not a recommended method to protect you from identity theft?
yaroslaw [1]

Answer:

post them, but id say anything with personal information

7 0
3 years ago
When a subdomain has been delegated to a zone on another server, the DNS server hosting the parent zone maintains only an NS rec
Vedmedyk [2.9K]

Answer:

True of False?

True

Explanation:

Different sub domains can be directed to different IPs servers but a client server cannot be forced to keep looking at name servers for additional records.

To delegate a subdomain to a zone on another server, one would need to add NS-records for the sub-domain name. This would point to the host names of the DNS servers hosting the sub-domain - in the parent zone.

In the "DNS records" window right-click the parent zone in the left list and select "New NS-record":

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A program in which students learn a specific skill for a particular job is called a
Ne4ueva [31]
A certification program.
7 0
3 years ago
Read 2 more answers
What may happen if a larger number of computer users are attempting to access a Web site at the same time that u r??? I think it
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I think if a large number are accessing at the same time you would have to wait for many to clear up

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